维基百科 3c 中的 Prims MST 没有意义

Prims MST from Wikipedia 3c not making sense

完成 Wiki Prims 示例 https://en.wikipedia.org/wiki/Prim%27s_algorithm

到达点 3c -

循环连接 v 和其他顶点 w 的边 vw。对于每条这样的边,如果w仍然属于Q并且vw的权重小于C[w],执行以下步骤:

设置C[w]为边vw的代价 设置 E[w] 指向边 vw.

所以,如果 vw < C[w] - 但如果 C[w] 已经设置为 "C[v] (the cheapest cost of a connection to v)" 那么任何边怎么可能小于可用的最佳边?

如果我让它 运行 我明白了..

这是我目前所拥有的...

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <meta http-equiv="X-UA-Compatible" content="ie=edge">
    <title>MST - Prims Algorithm Solution</title>
    <style>
        body { padding: 0px; margin: 0px; }
        canvas {
            background-image: url('./gfx/map25.png');
            width: 2000px;
            height: 1100px;
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        class Place {
            constructor(name, x, y, id) {
                this.id = id;
                this.name = name;
                this.x = x;
                this.y = y;
                this.edges = [];
                this.C = 99999; // Wiki - the cheapest cost of a connection to v
                this.E = null; // Wiki - the edge providing that cheapest connection
            }
        }
        class Edge {
            constructor(node1, node2, id) {
                this.id = id;
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                this.node2 = node2;
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            get distance() {
                let dx = this.node1.x - this.node2.x;
                let dy = this.node1.y - this.node2.y;
                return Math.sqrt( dx*dx + dy*dy );
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        let edges = [];
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        // Setup the canvas bits
        const canvas = document.getElementById("map");
        const ctx = canvas.getContext("2d");
        canvas.width = 2000;
        canvas.height = 1100;

        // The forest (F) and visited list (Q)
        let F = {places: [], edges: []};
        let Q = [];

        document.addEventListener("DOMContentLoaded", ()=> {
            // Create the nodes / place instances
            placeData.forEach((place)=>{
                places.push(new Place(place.name, place.x, place.y, place.id));
            });
            // Create the edges with their nodes
            edgeData.forEach((edge)=>{
                edges.push(new Edge(places[edge.node1.id-1], places[edge.node2.id-1], edges.length+1 ));
            });
            // Update nodes with their edges
            edges.forEach((edge)=>{
                edge.node1.edges.push(edge);
                edge.node2.edges.push(edge);
            });

            /**
             *  Wiki - Associate with each vertex v of the graph a number C[v] (the cheapest cost of a connection to v)
             *         and an edge E[v] (the edge providing that cheapest connection). To initialize these values, set all
             *         values of C[v] to +∞ (or to any number larger than the maximum edge weight) and set each E[v] to a
             *         special flag value indicating that there is no edge connecting v to earlier vertices.
             */
            places.forEach((place)=>{
                let C = 99999;
                let E = null;
                place.edges.forEach((edge)=>{
                    if(edge.distance < C) {
                        C = edge.distance;
                        E = edge;
                    }
                });
                place.C = C;
                place.E = E;
            });

            /* Draw everything we have, places (nodes), routes (edges), E[v] (best edge), distances */
            ctx.clearRect(0, 0, canvas.width, canvas.height);
            drawEdges();
            drawPlaceE();
            drawPlaces();
            drawDistances();

            /**
             *  Wiki - Initialize an empty forest F and a set Q of vertices that have not yet been
             *         included in F (initially, all vertices).
             */
            F = {places: [], edges: []};
            places.forEach((place)=>{
                Q.push(place);
            });
            console.log(`Step 1 : F, Q`,F ,Q);

            /**
             *  Wiki - Repeat the following steps until Q is empty:
             */
             step(1);

        });

        /* The Prim algorithm */
        function step(n) {

            for(let l = 0; l < n; l+=1) {

                /**
                 *  Wiki - Find and remove a vertex v from Q having the minimum possible value of C[v]
                 */
                let lowestC = 99999;
                let lowestPlace = null;
                let lowestIndex = 0;
                Q.forEach((place, index)=>{
                    if(place.C < lowestC) {
                        lowestC = place.C;
                        lowestPlace = place;
                        lowestIndex = index;
                    }
                });
                Q.splice(lowestIndex, 1);

                /**
                 *  Wiki - Add v to F and, if E[v] is not the special flag value, also add E[v] to F
                 */
                F.places.push(lowestPlace);
                if(lowestPlace.E !== null) {
                    F.edges.push(lowestPlace.E);
                    lowestPlace.E = null;
                }
                console.log(`Step end : F, Q`,F ,Q);

                /* Draw the forest after this step ... */
                drawF();

                /**
                 *  Wiki - Loop over the edges vw connecting v to other vertices w.
                 */

                /**
                 *  Wiki - For each such edge, if w still belongs to Q and vw has
                 *         smaller weight than C[w], perform the following steps:
                 */

                /**
                 *  Wiki - Set C[w] to the cost of edge vw
                 *         Set E[w] to point to edge vw
                 */
            }
        }
        /* Draw the F edges, the final MST */
        function drawF() {
            F.edges.forEach((edge)=>{
                ctx.beginPath();
                ctx.strokeStyle = "red";
                ctx.lineWidth = 4;
                ctx.moveTo(edge.node1.x, edge.node1.y);
                ctx.lineTo(edge.node2.x, edge.node2.y);
                ctx.stroke();
            });
        }
        /* Draw the E (edge with lowest cost to get to the place) */
        function drawPlaceE() {
            places.forEach((place)=>{
                ctx.beginPath();
                ctx.strokeStyle = "green";
                ctx.lineWidth = 2;
                ctx.moveTo(place.E.node1.x, place.E.node1.y);
                ctx.lineTo(place.E.node2.x, place.E.node2.y);
                ctx.stroke();
            });
        }
        /* Draw the places */
        function drawPlaces() {
            ctx.fillStyle = "red";
            places.forEach((place)=>{
                ctx.fillRect(place.x-5, place.y-5, 10, 10);
            });
        }
        /* Draw the edges - lines connecting the places */
        function drawEdges() {
            edges.forEach((edge)=>{
                ctx.beginPath();
                ctx.strokeStyle = "grey";
                ctx.moveTo(edge.node1.x, edge.node1.y);
                ctx.lineTo(edge.node2.x, edge.node2.y);
                ctx.stroke();
            });
        }
        /* Draw the distance box on top of the edge */
        function drawDistances() {
            edges.forEach((edge)=>{
                let cx = (( edge.node1.x + edge.node2.x ) / 2) - 15;
                let cy = (( edge.node1.y + edge.node2.y ) / 2) - 7;
                ctx.fillStyle = "blue";
                ctx.fillRect(cx, cy, 30, 15);
                ctx.font = "12px Arial";
                ctx.fillStyle = "white";
                ctx.fillText(`${Math.floor(edge.distance)}`, cx+5, cy+11);

            });
        }

    </script>
</body>
</html>

C[v] 更具体地说是最便宜的传入边 ,其另一个端点不属于 Q。初始化应该是

            place.C = Infinity;
            place.E = null;