Spring 集成Jpa |在 java dsl 中使用 Jpa 插入行

Spring integration Jpa | To insert row with Jpa in java dsl

我在互联网上搜索了很多,但找不到以下内容的句柄:

插入行的具体示例JpaUpdatingOutboundEndpointSpec

@Bean
public JpaUpdatingOutboundEndpointSpec insertToTable() {
    return Jpa.updatingGateway(entityManger)
              .entityClass(EntitySample.class); 
}

以上够了吗?

请帮助我。

没错,在某些情况下,该代码可能就足够了。从这里知道您将如何使用此代码会很棒。虽然同时我会与您分享我的测试配置和测试本身:

    @Bean
    public IntegrationFlow outboundAdapterFlow(EntityManagerFactory entityManagerFactory) {
        return f -> f
                .handle(Jpa.outboundAdapter(entityManagerFactory)
                                .entityClass(StudentDomain.class)
                                .persistMode(PersistMode.PERSIST),
                        e -> e.transactional(true));
    }

...

@Autowired
@Qualifier("outboundAdapterFlow.input")
private MessageChannel outboundAdapterFlowInput;

@Test
public void testOutboundAdapterFlow() {
    JdbcTemplate jdbcTemplate = new JdbcTemplate(dataSource);

    List<?> results1 = jdbcTemplate.queryForList("Select * from Student");
    assertNotNull(results1);
    assertTrue(results1.size() == 3);

    Calendar dateOfBirth = Calendar.getInstance();
    dateOfBirth.set(1981, 9, 27);

    StudentDomain student = new StudentDomain()
            .withFirstName("Artem")
            .withLastName("Bilan")
            .withGender(Gender.MALE)
            .withDateOfBirth(dateOfBirth.getTime())
            .withLastUpdated(new Date());

    assertNull(student.getRollNumber());

    this.outboundAdapterFlowInput.send(MessageBuilder.withPayload(student).build());

    List<?> results2 = jdbcTemplate.queryForList("Select * from Student");
    assertNotNull(results2);
    assertTrue(results2.size() == 4);

    assertNotNull(student.getRollNumber());
}

您可以在框架的测试 class 中找到更多关于 Spring 集成 Java DSL for JPA 的测试:https://github.com/spring-projects/spring-integration/blob/master/spring-integration-jpa/src/test/java/org/springframework/integration/jpa/dsl/JpaTests.java