如何在 ListView 中重新排列数据库中的数据？

Question

各位。我有一个 ArrayList 数据和一个 ListView 来显示数据列表。现在我要做的是在按下按钮时重新排列数据，并对数据结果最高的数据进行排序。

这是我的代码：

public class MainActivity extends AppCompatActivity {

private TextView mTextMessage;

String[] dataDetail;
ArrayList<dataDetail> allDetail = new ArrayList<>();

ListView detailList;
final Context context = this;

final int min = 0;
final int max = 10;
final int random = new Random().nextInt((max - min) + 1) + min;

Button reorder = findViewById(R.id.arrangeId);

private BottomNavigationView.OnNavigationItemSelectedListener mOnNavigationItemSelectedListener
        = new BottomNavigationView.OnNavigationItemSelectedListener() {

    @Override
    public boolean onNavigationItemSelected(@NonNull MenuItem item) {
        switch (item.getItemId()) {
            case R.id.navigation_home:
                mTextMessage.setText(R.string.title_home);
                return true;
            case R.id.navigation_dashboard:
                mTextMessage.setText(R.string.title_dashboard);
                return true;
        }
        return false;
    }
};

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    detailList = findViewById(R.id.dataView);

    mTextMessage = (TextView) findViewById(R.id.message);
    BottomNavigationView navigation = (BottomNavigationView) findViewById(R.id.navigation);
    navigation.setOnNavigationItemSelectedListener(mOnNavigationItemSelectedListener);

    new GetData().execute();

}

private class GetData extends AsyncTask<Void, Void, ArrayList<dataDetail>> {

    protected ArrayList<dataDetail> doInBackground(Void... voids) {

        HttpURLConnection urlConnection;
        InputStream in = null;
        try {
            URL url = new URL("http://10.0.2.2:8080/projectServer/DataDetailDB?getdata=true");
            urlConnection = (HttpURLConnection) url.openConnection();
            in = new BufferedInputStream(urlConnection.getInputStream());
        } catch (IOException e) {
            e.printStackTrace();
        }
        String response = convertStreamToString(in);
        System.out.println("Server response = " + response);

        try {
            JSONArray jsonArray = new JSONArray(response);
            dataDetail = new String[jsonArray.length()];

            for (int i = 0; i < jsonArray.length(); i++) {

               final String customerName = jsonArray.getJSONObject(i).get("customerName").toString();
               final String carName = jsonArray.getJSONObject(i).get("carName").toString();
               final String appointmentDate = jsonArray.getJSONObject(i).get("appointmentDate").toString();
               final String email = jsonArray.getJSONObject(i).get("email").toString();
               final String issueDescribe = jsonArray.getJSONObject(i).get("issueDescribe").toString();
               final String timeForJob = jsonArray.getJSONObject(i).get("timeForJob").toString();
               final String costForJob = jsonArray.getJSONObject(i).get("costForJob").toString();
               final String reliableOnCar = jsonArray.getJSONObject(i).get("reliableOnCar").toString();
               final String distanceJob = jsonArray.getJSONObject(i).get("distance").toString();

                dataDetail tData = new dataDetail(customerName, carName, appointmentDate, email, issueDescribe, timeForJob, costForJob, reliableOnCar, distanceJob);
                allDetail.add(tData);

                System.out.println("customername = " + customerName + "carname = " + carName + "appointmentdate = " + appointmentDate +
                    "email = " + email + "describe = " + issueDescribe + "time = " + timeForJob + "cost = " + costForJob + "reliable = " + reliableOnCar
                + "dis = " + distanceJob);

                dataDetail [i] = "Name: " + customerName + "\n" + "Appointment Date: " + appointmentDate;


                reorder.setOnClickListener(new View.OnClickListener() {
                    @Override
                    public void onClick(View v) {


                        float finalResult = random * Float.parseFloat(timeForJob) + random * Float.parseFloat(reliableOnCar) +
                                random * Float.parseFloat(distanceJob) + random * Float.parseFloat(costForJob);

                        System.out.print("Test result " + finalResult + " ");

                        /* Trying to sort the data here which has the highest finalResult
                        *  will going to the top of the list */

                        allDetail = new ArrayList<String>(Arrays.asList(dataDetail));
                        Collections.sort(allDetail);

                        ArrayAdapter newList = new ArrayAdapter(context, android.R.layout.simple_list_item_1, dataDetail);
                        newList.setAdapter(theList);

                    }
                });


            }

        } catch (JSONException e) {
            e.printStackTrace();
        }

        return null;
    }

    protected void onPostExecute(ArrayList<dataDetail> dataDetailArrayList) {
        super.onPostExecute(dataDetailArrayList);

        ArrayAdapter theList = new ArrayAdapter(context, android.R.layout.simple_list_item_1, dataDetail);
        detailList.setAdapter(theList);
    }
}

public String convertStreamToString(InputStream is) {
    java.util.Scanner s = new java.util.Scanner(is).useDelimiter("\A");
    return s.hasNext() ? s.next() : "";
}

}

但是当我尝试使用 sort 时，我收到错误消息说它是不兼容的类型。

allDetail = new ArrayList<String>(Arrays.asList(dataDetail));
Collections.sort(allDetail);

finalResult 将对从数据库中检索的每条数据进行计算并获得最终结果。现在我只想自动重新排序，这是 logcat:

任何人都可以帮助我如何重新排列列表视图？

Answer 1

Collections.sort() 会起作用。您的问题与您如何将数据存储在 list

中有关

如何在 ListView 中重新排列数据库中的数据？

How can I rearrange the data from database in a ListView?

android

listview

android-arrayadapter