SQL 服务器 2008:将来自子 table 的 3 table 和 select 最后输入的记录加入每个父记录
SQL server 2008: join 3 tables and select last entered record from child table against each parent record
我有以下 3 table 和最后输入的原因代码来自 Reasons table 针对每个 claimno 索赔 table.
原因:
Rid |chargeid| enterydate user reasoncode
-----|--------|-------------|--------|----------
1 | 210 | 04/03/2018 | john | 99
2 | 212 | 05/03/2018 | juliet | 24
5 | 212 | 26/12/2018 | umar | 55
3 | 212 | 07/03/2018 | borat | 30
4 | 211 | 03/03/2018 | Juliet | 20
6 | 213 | 03/03/2018 | borat | 50
7 | 213 | 24/12/2018 | umer | 60
8 | 214 | 01/01/2019 | john | 70
费用:
chargeid |claim# | amount
---------|-------|---------
210 | 1 | 10
211 | 1 | 24.2
212 | 2 | 5.45
213 | 2 | 76.30
214 | 1 | 2.10
索赔:
claimno | Code | Code
--------|-------|------
1 | AH22 | AH22
2 | BB32 | BB32
预期结果是这样的:
claimno | enterydate | user | reasoncode
--------|-------------|--------|-----------
1 | 01/01/2019 | john | 70
2 | 26/12/2018 | umer | 55
我应用了很多解决方案,但没有成功。以下是我尝试使用 SQL Server 2008 但仍然得到不正确结果的最新解决方案。
With x As
(
select r.chargeid,r.enterydate,ch.claimno from charges ch
join (select chargeid,max(enterydate) enterydate,user from Reasons group by chargeid) r on r.chargeid = ch.chargeid
)
select x.*,r1.user, r1.reasoncode from x
left outer join Reasons r1 on r1.chargeid = x.chargeid and r1.enterydate = x.enterydate
--group by x.claimno
您可以尝试使用 row_number()
select * from
(
select r.chargeid,r.enterydate,ch.claimno,user,reasoncode,
row_number() over(partition by ch.claimno order by r1.enterydate desc) as rn
from charges ch left outer join Reasons r1 on r1.chargeid = ch.chargeid
)A where rn=1
这是你想要的吗?
select claimno, enterydate, user, reasoncode
from (select c.claimno, r.*,
row_number() over (partition by c.claimno order by r.entrydate desc) as seqnum
from charges c join
reasons r
on c.chargeid = r.chargeid
) cr
where seqnum = 1;
我有以下 3 table 和最后输入的原因代码来自 Reasons table 针对每个 claimno 索赔 table.
原因:
Rid |chargeid| enterydate user reasoncode
-----|--------|-------------|--------|----------
1 | 210 | 04/03/2018 | john | 99
2 | 212 | 05/03/2018 | juliet | 24
5 | 212 | 26/12/2018 | umar | 55
3 | 212 | 07/03/2018 | borat | 30
4 | 211 | 03/03/2018 | Juliet | 20
6 | 213 | 03/03/2018 | borat | 50
7 | 213 | 24/12/2018 | umer | 60
8 | 214 | 01/01/2019 | john | 70
费用:
chargeid |claim# | amount
---------|-------|---------
210 | 1 | 10
211 | 1 | 24.2
212 | 2 | 5.45
213 | 2 | 76.30
214 | 1 | 2.10
索赔:
claimno | Code | Code
--------|-------|------
1 | AH22 | AH22
2 | BB32 | BB32
预期结果是这样的:
claimno | enterydate | user | reasoncode
--------|-------------|--------|-----------
1 | 01/01/2019 | john | 70
2 | 26/12/2018 | umer | 55
我应用了很多解决方案,但没有成功。以下是我尝试使用 SQL Server 2008 但仍然得到不正确结果的最新解决方案。
With x As
(
select r.chargeid,r.enterydate,ch.claimno from charges ch
join (select chargeid,max(enterydate) enterydate,user from Reasons group by chargeid) r on r.chargeid = ch.chargeid
)
select x.*,r1.user, r1.reasoncode from x
left outer join Reasons r1 on r1.chargeid = x.chargeid and r1.enterydate = x.enterydate
--group by x.claimno
您可以尝试使用 row_number()
select * from
(
select r.chargeid,r.enterydate,ch.claimno,user,reasoncode,
row_number() over(partition by ch.claimno order by r1.enterydate desc) as rn
from charges ch left outer join Reasons r1 on r1.chargeid = ch.chargeid
)A where rn=1
这是你想要的吗?
select claimno, enterydate, user, reasoncode
from (select c.claimno, r.*,
row_number() over (partition by c.claimno order by r.entrydate desc) as seqnum
from charges c join
reasons r
on c.chargeid = r.chargeid
) cr
where seqnum = 1;