在 laravel 迁移中使用 UUID 作为默认值

Using UUID as default value in a laravel migration

我有以下迁移:

<?php

use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class UpdateRatingGameUserAnswersTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::table('rating_games_user_answers', function (Blueprint $table) {
            $table->uuid('answer_token')->default(DB::raw('UUID()'));
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::table('rating_games_user_answers', function (Blueprint $table) {
            $table->dropColumn('answer_token');
        });
    }
}

如您所见,我正在尝试将 UUID 设置为默认值。我看过了 here

但是当我 运行 php artisan migrate 我看到以下内容:

怎么了?

您不能使用 mySQL 函数作为默认值,您应该设置它或使用触发器。

请像这样尝试:

<?php

use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class UpdateRatingGameUserAnswersTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::table('rating_games_user_answers', function (Blueprint $table) {
            $uuid = DB::raw('select UUID()');
            $table->uuid('answer_token')->default($uuid);
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::table('rating_games_user_answers', function (Blueprint $table) {
            $table->dropColumn('answer_token');
        });
    }
}

当我遇到同样的问题时遇到这个问题: 使用 MySQL 8,您 可以 使用函数作为默认值。但是你需要在它们周围加上括号。所以这有效:

$table->uuid('uid')->default(DB::raw('(UUID())'));

但这与 MySQL 5.7 不兼容!