从变量设置 *args？

Question

是否可以从变量设置 *args？

def fn(x, *args):
    # ...

# pass arguments not as list but each as single argument
arguments = ??? # i.e.: ['a', 'b']


fn(1, arguments)

# should be equivalent to
fn(1, 'a', 'b')

Answer 1

是的，您可以使用参数解包（也称为展开）：

fn(1, *arguments)

下面是演示：

>>> def fn(x, *args):
...     return args
...
>>> arguments = ['a', 'b']
>>> fn(1, *arguments)
('a', 'b')
>>>

Answer 2

# pass arguments not as list but each as single argument
arguments = ??? # i.e.: ['a', 'b']

然后应分配参数 arguments = ['a' ,'b']。这是参数拆包。