下载后 C# 文件夹中没有数据 ASP
C# No Data in Folder after Downloading ASP
首先让我说我确定这很简单,不幸的是我似乎无法弄清楚。所以这是我的问题,我查询数据库,return 我需要什么,把它全部压缩,然后提示用户保存。当您尝试打开它时,文件夹内没有任何文件。我的数据去哪儿了?我逐步完成了所有内容,并且似乎正确地编写了所有内容。任何帮助将不胜感激!!
if (e.CommandName == "DownloadAttachment")
{
e.Canceled = true;
// Create a zip and send it to the client.
//Response.Write(@"<script language='javascript'>alert('Details saved successfully')</script>");
var item = e.Item as GridEditableItem;
fileId = (int)item.GetDataKeyValue("Unique");
FileData[] allrecords = null;
using (
SqlConnection conn =
new SqlConnection(ConfigurationManager.ConnectionStrings["PtcDbModelEntities"].ConnectionString))
{
using (
SqlCommand comm = new SqlCommand("Select Unique1, BinaryData, FileName from PtcDbTracker.dbo.CafFileTable where Unique1=@fileId AND FileName IS NOT NULL", conn))
{
comm.Parameters.Add(new SqlParameter("@fileId", fileId));
conn.Open();
using (var reader = comm.ExecuteReader())
{
var list = new List<FileData>();
while (reader.Read())
{
list.Add(new FileData { Unique1 = reader.GetInt32(0) });
long len = reader.GetBytes(1, 0, null, 0, 0);
Byte[] buffer = new byte[len];
list.Add(new FileData { BinaryData = (byte)reader.GetBytes(1, 0, buffer, 0, (int)len), FileName = reader.GetString(2) });
allrecords = list.ToArray();
}
}
conn.Close();
}
}
using (var compressedFileStream = new MemoryStream())
{
//Create an archive and store the stream in memory.
using (var zipArchive = new ZipArchive(compressedFileStream, ZipArchiveMode.Update, false))
{
if (allrecords != null)
{
foreach (var record in allrecords)
{
//Create a zip entry for each attachment
if (record.FileName != null)
{
var zipEntry = zipArchive.CreateEntry(record.FileName);
//Get the stream of the attachment
using (var originalFileStream = new MemoryStream(record.BinaryData))
{
using (var zipEntryStream = zipEntry.Open())
{
//Copy the attachment stream to the zip entry stream
originalFileStream.CopyTo(zipEntryStream);
}
}
}
}
}
Response.ClearContent();
Response.ClearHeaders();
Response.BinaryWrite(compressedFileStream.ToArray());
Response.AppendHeader("Content-Disposition", "Attachment; filename=result.zip");
Response.Flush();
Response.Close();
zipArchive.Dispose();
//How Do I Prompt for open or save?
}
}
您确定 BinaryWrite 正在获取有效的 ByteArray 吗?
无论如何,这里有一个经过测试的方法,可以将文件输出到响应,通常需要 headers 用于二进制附件:
public bool WriteFile(byte[] byteContent, DateTime dtTimeStamp, string urlFilename)
{
HttpContext context = HttpContext.Current;
HttpResponse response = context.Response;
response.Clear();
response.ClearHeaders();
response.ClearContent();
response.BufferOutput = true;
response.AppendHeader("Content-Length", byteContent.Length.ToString());
response.AppendHeader("Content-Type", "application/octet-stream");
response.AppendHeader("Last-Modified", dtTimeStamp.ToString("R"));//Last-Modified Wed, 28 Aug 2013 10:16:46 GMT
response.AppendHeader("Content-Disposition", "inline; filename=\"" + urlFilename + "\"");
response.BinaryWrite(byteContent);
response.Flush();
// Prevents any other content from being sent to the browser
response.SuppressContent = true;
context.ApplicationInstance.CompleteRequest();
return true;
}
首先让我说我确定这很简单,不幸的是我似乎无法弄清楚。所以这是我的问题,我查询数据库,return 我需要什么,把它全部压缩,然后提示用户保存。当您尝试打开它时,文件夹内没有任何文件。我的数据去哪儿了?我逐步完成了所有内容,并且似乎正确地编写了所有内容。任何帮助将不胜感激!!
if (e.CommandName == "DownloadAttachment")
{
e.Canceled = true;
// Create a zip and send it to the client.
//Response.Write(@"<script language='javascript'>alert('Details saved successfully')</script>");
var item = e.Item as GridEditableItem;
fileId = (int)item.GetDataKeyValue("Unique");
FileData[] allrecords = null;
using (
SqlConnection conn =
new SqlConnection(ConfigurationManager.ConnectionStrings["PtcDbModelEntities"].ConnectionString))
{
using (
SqlCommand comm = new SqlCommand("Select Unique1, BinaryData, FileName from PtcDbTracker.dbo.CafFileTable where Unique1=@fileId AND FileName IS NOT NULL", conn))
{
comm.Parameters.Add(new SqlParameter("@fileId", fileId));
conn.Open();
using (var reader = comm.ExecuteReader())
{
var list = new List<FileData>();
while (reader.Read())
{
list.Add(new FileData { Unique1 = reader.GetInt32(0) });
long len = reader.GetBytes(1, 0, null, 0, 0);
Byte[] buffer = new byte[len];
list.Add(new FileData { BinaryData = (byte)reader.GetBytes(1, 0, buffer, 0, (int)len), FileName = reader.GetString(2) });
allrecords = list.ToArray();
}
}
conn.Close();
}
}
using (var compressedFileStream = new MemoryStream())
{
//Create an archive and store the stream in memory.
using (var zipArchive = new ZipArchive(compressedFileStream, ZipArchiveMode.Update, false))
{
if (allrecords != null)
{
foreach (var record in allrecords)
{
//Create a zip entry for each attachment
if (record.FileName != null)
{
var zipEntry = zipArchive.CreateEntry(record.FileName);
//Get the stream of the attachment
using (var originalFileStream = new MemoryStream(record.BinaryData))
{
using (var zipEntryStream = zipEntry.Open())
{
//Copy the attachment stream to the zip entry stream
originalFileStream.CopyTo(zipEntryStream);
}
}
}
}
}
Response.ClearContent();
Response.ClearHeaders();
Response.BinaryWrite(compressedFileStream.ToArray());
Response.AppendHeader("Content-Disposition", "Attachment; filename=result.zip");
Response.Flush();
Response.Close();
zipArchive.Dispose();
//How Do I Prompt for open or save?
}
}
您确定 BinaryWrite 正在获取有效的 ByteArray 吗?
无论如何,这里有一个经过测试的方法,可以将文件输出到响应,通常需要 headers 用于二进制附件:
public bool WriteFile(byte[] byteContent, DateTime dtTimeStamp, string urlFilename)
{
HttpContext context = HttpContext.Current;
HttpResponse response = context.Response;
response.Clear();
response.ClearHeaders();
response.ClearContent();
response.BufferOutput = true;
response.AppendHeader("Content-Length", byteContent.Length.ToString());
response.AppendHeader("Content-Type", "application/octet-stream");
response.AppendHeader("Last-Modified", dtTimeStamp.ToString("R"));//Last-Modified Wed, 28 Aug 2013 10:16:46 GMT
response.AppendHeader("Content-Disposition", "inline; filename=\"" + urlFilename + "\"");
response.BinaryWrite(byteContent);
response.Flush();
// Prevents any other content from being sent to the browser
response.SuppressContent = true;
context.ApplicationInstance.CompleteRequest();
return true;
}