PostgreSQL,unnest array into values
PostgreSQL, unnest array into values
假设我有文本输入:
周六购买,XXX 送货,地址 YYY,付款方式 ZZZ
请向我们提供价格和库存情况
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в
如何修改这个查询,这样我就不需要手动拆分行了?
with long_string (ls) as (values
('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ'),
('Please quote us on prices and stock availability'),
('К52-1Б - 68мкф/50в'),
('К52-1 - 100мкф/63в')
)
select products.*, matches, similarity
from products
cross join long_string
cross join lateral
(select
(name % ls)::int as matches,
similarity(name, ls) as similarity
) m
where matches > 0 and similarity > 0.7
order by matches desc, similarity desc;
我试过了
with long_string (ls) as (
values
unnest(string_to_array('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ
Please quote us on prices and stock availability
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в', '\n'))
)
select products.*, matches, similarity
....
但是有错误ERROR: syntax error at or near "unnest"
如果这只是解析字符串,那么:
with long_string (ls) as (
select unnest(string_to_array(str, E'\n'))
from (values ('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ
Please quote us on prices and stock availability
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в')
) v(str)
)
select ls
from long_string;
Here 是一个 db<>fiddle.
或者您可以这样做:
with long_string (ls) as (
select
trim(regexp_split_to_table('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ
Please quote us on prices and stock availability
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в', '\n'))
)
select *
from long_string
假设我有文本输入:
周六购买,XXX 送货,地址 YYY,付款方式 ZZZ
请向我们提供价格和库存情况
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в
如何修改这个查询,这样我就不需要手动拆分行了?
with long_string (ls) as (values
('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ'),
('Please quote us on prices and stock availability'),
('К52-1Б - 68мкф/50в'),
('К52-1 - 100мкф/63в')
)
select products.*, matches, similarity
from products
cross join long_string
cross join lateral
(select
(name % ls)::int as matches,
similarity(name, ls) as similarity
) m
where matches > 0 and similarity > 0.7
order by matches desc, similarity desc;
我试过了
with long_string (ls) as (
values
unnest(string_to_array('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ
Please quote us on prices and stock availability
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в', '\n'))
)
select products.*, matches, similarity
....
但是有错误ERROR: syntax error at or near "unnest"
如果这只是解析字符串,那么:
with long_string (ls) as (
select unnest(string_to_array(str, E'\n'))
from (values ('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ
Please quote us on prices and stock availability
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в')
) v(str)
)
select ls
from long_string;
Here 是一个 db<>fiddle.
或者您可以这样做:
with long_string (ls) as (
select
trim(regexp_split_to_table('Buying on Saturday, delivery by XXX, address YYY, payment method ZZZ
Please quote us on prices and stock availability
К52-1Б - 68мкф/50в
К52-1 - 100мкф/63в', '\n'))
)
select *
from long_string