NoSuchElementException：消息：尝试通过 Selenium 和 Python 单击按钮 VISA 时无法定位元素

Question

我无法单击此按钮在我的机器人上创建结帐。我想点击图片进入另一个页面。

<label for="VISA" class="choiceLabel">
            
    <input type="radio" class="visuallyhidden" name="cardTypeRadio" id="VISA" value="VISA" title="VISA" onclick="validateAndSubmit('VISA');">
     <span class="imgElt xh-highlight" onclick="validateAndSubmit('VISA');">
               <img src="/static/2.15.0.1/images/type-carte/visa.png" alt="VISA" title="Visa">
             </span>
            <span class="txtElt">Visa</span>
          </label>

这是我的代码：

try:
             check = WebDriverWait(driver, delay).until(EC.presence_of_element_located((By.ID,"VISA" )))
            
             print ("Page is ready!")
             visa = driver.find_elements_by_xpath("label[@class='choiceLabel'][4]")
             visa.click()


        except TimeoutException:
             print ("Loading took too much time!")
             return check

我收到此错误：

 File "C:\Users\x\AppData\Local\Programs\Python\Python37\lib\threading.py", line 917, in _bootstrap_inner
    self.run()
  File "C:\Users\x\AppData\Local\Programs\Python\Python37\lib\threading.py", line 865, in run
    self._target(*self._args, **self._kwargs)
  File "c:/Users/pietro/Documents/monitor/x/bot.py", line 48, in all
    visa = driver.find_element_by_xpath("label[@class='choiceLabel'][4]")
  File "C:\Users\x\AppData\Local\Programs\Python\Python37\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 394, in find_element_by_xpath
    return self.find_element(by=By.XPATH, value=xpath)
  File "C:\Users\x\AppData\Local\Programs\Python\Python37\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 978, in find_element
    'value': value})['value']
  File "C:\Users\x\AppData\Local\Programs\Python\Python37\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 321, in execute
    self.error_handler.check_response(response)
  File "C:\Users\x\AppData\Local\Programs\Python\Python37\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 242, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: label[@class='choiceLabel'][4]

Answer 1

您正在搜索的 xPath 可能看起来更像这样：

//input[@name='cardTypeRadio' and @value='VISA']

如果这不能为您提供独特的元素，我们可以对其进行一些改进。

Answer 2

可能你的 xpath 是 wrong.Try 下面这个 code.Hope 这有帮助。

driver.find_element_by_xpath("//input[@name='cardTypeRadio']").click()

或

driver.find_element_by_xpath("//input[@id='VISA']").click()

如果webdriver点击不work.TryJavaScript点击。

driver.execute_script("arguments[0].click();", driver.find_element_by_xpath("//input[@name='cardTypeRadio']"))

driver.execute_script("arguments[0].click();", driver.find_element_by_xpath("//input[@id='VISA']"))

Answer 3

在我的机器人上创建结帐的按钮似乎是一个 信用卡 相关字段并且历史上 信用Card 相关字段位于 <iframe>.

内

您可以在以下位置找到一些相关讨论：

因此，如果所需元素在 <iframe> 内，那么您必须：

诱导 WebDriverWait 以获得所需的 框架并切换到它.
诱导 WebDriverWait 使所需的 元素可点击。

您可以使用以下任一解决方案：

使用CSS_SELECTOR:

WebDriverWait(driver, 20).until(EC.frame_to_be_available_and_switch_to_it((By.CSS_SELECTOR,"iframe_css_selector")))
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "label[for='VISA']"))).click()

使用XPATH:

WebDriverWait(driver, 20).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH,"//iframe_xpath")))
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//label[@for='VISA']"))).click()

注意：您必须添加以下导入：

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

NoSuchElementException：消息：尝试通过 Selenium 和 Python 单击按钮 VISA 时无法定位元素

NoSuchElementException: Message: Unable to locate element while trying to click on the button VISA through Selenium and Python

python

selenium

xpath

css-selectors

webdriverwait