std::lock_guard 使用可变参数模板
std::lock_guard with variadic templates
[无需点击链接即可理解问题]。
我在this answer, together with the synchronized file writing of 中结合了单例模式的实现。
然后我想看看 SynchronizedFile
的接口是否可以提供可变参数模板 write
方法,但我不知道如何将它与 std::lock_guard
正确地结合起来.
下面是一个无效的示例。在这种情况下,它不起作用,因为(我认为)两个线程设法以非同步方式将内容泵入缓冲区 i_buf
,导致乱码 LOGFILE.txt
。
如果我将 std::lock_guard
放在 write
的通用模板中,那么程序不会停止。
#include <iostream>
#include <mutex>
#include <sstream>
#include <fstream>
#include <string>
#include <memory>
#include <thread>
static const int N_LOOP_LENGTH{10};
// This class manages a log file and provides write method(s)
// that allow passing a variable number of parameters of different
// types to be written to the file in a line and separated by commas.
class SynchronizedFile {
public:
static SynchronizedFile& getInstance()
{
static SynchronizedFile instance;
return instance;
}
private:
std::ostringstream i_buf;
std::ofstream i_fout;
std::mutex _writerMutex;
SynchronizedFile () {
i_fout.open("LOGFILE.txt", std::ofstream::out);
}
public:
SynchronizedFile(SynchronizedFile const&) = delete;
void operator=(SynchronizedFile const&) = delete;
template<typename First, typename... Rest>
void write(First param1, Rest...param)
{
i_buf << param1 << ", ";
write(param...);
}
void write()
{
std::lock_guard<std::mutex> lock(_writerMutex);
i_fout << i_buf.str() << std::endl;
i_buf.str("");
i_buf.clear();
}
};
// This is just some class that is using the SynchronizedFile class
// to write stuff to the log file.
class Writer {
public:
Writer (SynchronizedFile& sf, const std::string& prefix)
: syncedFile(sf), prefix(prefix) {}
void someFunctionThatWritesToFile () {
syncedFile.write(prefix, "AAAAA", 4343, "BBBBB", 0.2345435, "GGGGGG");
}
private:
SynchronizedFile& syncedFile;
std::string prefix;
};
void thread_method()
{
SynchronizedFile &my_file1 = SynchronizedFile::getInstance();
Writer writer1(my_file1, "Writer 1:");
for (int i = 0; i < N_LOOP_LENGTH; ++ i)
writer1.someFunctionThatWritesToFile();
}
int main()
{
std::thread t(thread_method);
SynchronizedFile &my_file2 = SynchronizedFile::getInstance();
Writer writer2(my_file2, "Writer 2:");
for (int i = 0; i < N_LOOP_LENGTH; ++i)
writer2.someFunctionThatWritesToFile();
t.join();
std::cout << "Done" << std::endl;
return 0;
}
我怎样才能成功地将这三个想法结合起来?
程序死锁,因为 write
在仍然持有锁的情况下递归调用自身。
要么使用 std::recursive_mutex
,要么在写完数据之后调用 write
之前释放锁。
E: 解锁不行,我没想通...
E: 或锁定一次并推迟到另一个私有方法进行写入。
template<typename... Args>
void write(Args&&... args)
{
std::unique_lock<std::mutex> lock(_writerMutex);
_write(std::forward<Args>(args)...);
}
template<typename First, typename... Rest>
void _write(First&& param1, Rest&&... param) // private method
{
i_buf << std::forward<First>(param1) << ", ";
_write(std::forward<Rest>(param)...);
}
void _write()
{
i_fout << i_buf.str() << std::endl;
i_buf.clear();
}
[无需点击链接即可理解问题]。
我在this answer, together with the synchronized file writing of
然后我想看看 SynchronizedFile
的接口是否可以提供可变参数模板 write
方法,但我不知道如何将它与 std::lock_guard
正确地结合起来.
下面是一个无效的示例。在这种情况下,它不起作用,因为(我认为)两个线程设法以非同步方式将内容泵入缓冲区 i_buf
,导致乱码 LOGFILE.txt
。
如果我将 std::lock_guard
放在 write
的通用模板中,那么程序不会停止。
#include <iostream>
#include <mutex>
#include <sstream>
#include <fstream>
#include <string>
#include <memory>
#include <thread>
static const int N_LOOP_LENGTH{10};
// This class manages a log file and provides write method(s)
// that allow passing a variable number of parameters of different
// types to be written to the file in a line and separated by commas.
class SynchronizedFile {
public:
static SynchronizedFile& getInstance()
{
static SynchronizedFile instance;
return instance;
}
private:
std::ostringstream i_buf;
std::ofstream i_fout;
std::mutex _writerMutex;
SynchronizedFile () {
i_fout.open("LOGFILE.txt", std::ofstream::out);
}
public:
SynchronizedFile(SynchronizedFile const&) = delete;
void operator=(SynchronizedFile const&) = delete;
template<typename First, typename... Rest>
void write(First param1, Rest...param)
{
i_buf << param1 << ", ";
write(param...);
}
void write()
{
std::lock_guard<std::mutex> lock(_writerMutex);
i_fout << i_buf.str() << std::endl;
i_buf.str("");
i_buf.clear();
}
};
// This is just some class that is using the SynchronizedFile class
// to write stuff to the log file.
class Writer {
public:
Writer (SynchronizedFile& sf, const std::string& prefix)
: syncedFile(sf), prefix(prefix) {}
void someFunctionThatWritesToFile () {
syncedFile.write(prefix, "AAAAA", 4343, "BBBBB", 0.2345435, "GGGGGG");
}
private:
SynchronizedFile& syncedFile;
std::string prefix;
};
void thread_method()
{
SynchronizedFile &my_file1 = SynchronizedFile::getInstance();
Writer writer1(my_file1, "Writer 1:");
for (int i = 0; i < N_LOOP_LENGTH; ++ i)
writer1.someFunctionThatWritesToFile();
}
int main()
{
std::thread t(thread_method);
SynchronizedFile &my_file2 = SynchronizedFile::getInstance();
Writer writer2(my_file2, "Writer 2:");
for (int i = 0; i < N_LOOP_LENGTH; ++i)
writer2.someFunctionThatWritesToFile();
t.join();
std::cout << "Done" << std::endl;
return 0;
}
我怎样才能成功地将这三个想法结合起来?
程序死锁,因为 write
在仍然持有锁的情况下递归调用自身。
要么使用 std::recursive_mutex
,要么在写完数据之后调用 之前释放锁。
E: 解锁不行,我没想通...write
E: 或锁定一次并推迟到另一个私有方法进行写入。
template<typename... Args>
void write(Args&&... args)
{
std::unique_lock<std::mutex> lock(_writerMutex);
_write(std::forward<Args>(args)...);
}
template<typename First, typename... Rest>
void _write(First&& param1, Rest&&... param) // private method
{
i_buf << std::forward<First>(param1) << ", ";
_write(std::forward<Rest>(param)...);
}
void _write()
{
i_fout << i_buf.str() << std::endl;
i_buf.clear();
}