在 C++11 中定义元组常量向量的更简洁方法

Question

我有一个常量元组向量，其中每个元组包含一个键、名称、数量、值。我是这样定义的-

// tuple of key, name, quantity, value
const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
    std::tuple<unsigned char, std::string, unsigned char, float>(0, "mango", 12, 1.01f),
    std::tuple<unsigned char, std::string, unsigned char, float>(4, "apple", 101, 22.02f),
    std::tuple<unsigned char, std::string, unsigned char, float>(21, "orange", 179, 39.03f),
};

在主函数中，我需要处理每个元组的索引和所有值。为简单起见，我使用以下方式打印它们-

for (int index = 0; index < myTable.size(); index++) {
    auto key = std::get<0>(myTable[index]);
    auto name = std::get<1>(myTable[index]);
    auto quantity = std::get<2>(myTable[index]);
    auto value = std::get<3>(myTable[index]);
    std::cout << " index: " << index
              << " key:" << (int)key
              << " name:" << name
              << " quantity:" << (int)quantity
              << " value:" << value
              << std::endl;
}

可见vector的定义方式不是很干净。 我希望有很多更干净的东西，比如下面的东西-

const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
    (0, "mango", 12, 1.01f),
    (4, "apple", 101, 22.02f),
    (21, "orange", 179, 39.03f),
};

在 C++11 中是否有更清晰的定义元组常量向量的方法？

Answer 1

您可以使用 {}:

const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
    {0, "mango", 12, 1.01f},
    {4, "apple", 101, 22.02f},
    {21, "orange", 179, 39.03f},
};

在 C++11 中定义元组常量向量的更简洁方法

Cleaner way of defining a constant vector of tuples in C++11

c++

c++11

vector

tuples

stdtuple