二十一点，python

Question

import random
import time

class card():
    def __init__(self):
         cardNum = ["1","2", "3", "4", "5", "6", "7", "8", "9", "10", "10", "10"]
        randNum = random.randint(0, len(cardNum) - 1)
        cardSuit = ["Hearts", "Clubs", "Diamonds", "Spades"]
        randSuit = random.randint(0, len(cardSuit) - 1)

        self.rank = cardNum[randNum]
        self.suit = cardSuit[randSuit]

    total1 = []
    total2 = []
    total1.append(self.rank)

    def printIntro():
        print("Blackjack (twenty-one) is a casino game played with cards.")
        print("the goal of game is to draw cards that total as close to 21 
points, as possibale")
        print("without going over( whose hand > 21 will bust). All face 
cards count as 10 points,")
        print("aces count as 1 or 11, and all other cards count their 
numeric value.")
        print("\nFirstly, your turn:")


    def displayCard(self):


        return (self.rank+ " of "+ self.suit)

    def totalScore(self, ans="Y"):
        total1 = []
        total2 = []

        if ans == "Y":
            totalscore1 = total1.append(self.rank)
            return totalscore1
            ans = "N"
        if ans == "N":
            totalscore2 = total2.append(self.rank)
            return totalscore2


    def aceOption(self, cards1, cards2):
        if "Ace" in cards1:
            print("You have an ACE!")
            opt = int(input("Would you like ACE to be 1 or 11?: "))

            if opt == "1":
                aceVal(1)
            elif opt == "11":
                aceVal(11)

        elif "Ace" in cards2:
            print("You have an ACE!")
            opt = int(input("Would you like ACE to be 1 or 11?: "))

            if opt == "1":
                aceVal(1)
            elif opt == "11":
                aceVal(11)

    def nextOption(self):
        opt = input("Would you like to (T)WIST, or (S)TICK?")
        if opt == "T":
            #make twist function
        elif opt == "S":
            #make stick function

#myCard = card()

class player():
    def __init__(self, name="bob"):
        self.cards = []
        self.name = name
        self.cards2 = []

    def dealer1go(self):
        for i in range(0, 1):
            newcard = card()
            self.cards2.append(newcard.displayCard())

    def player1go(self):
        for i in range(0, 1):
            newcard = card()
            self.cards.append(newcard.displayCard())

class totalAmount():
    def __init__(self):
        pass




player1 = player("Matt")
dealer = player("Kieron")
deck = card()
intro =card.printIntro()
print(" ")
print(intro)


print("\nPlayer1 is dealt two cards..")
print("-------------------------------\n")
time.sleep(1)
print("\nDealer has two cards..")
print("-------------------------------\n")
time.sleep(1)

for i in range(1, 3):
    player1.player1go()
    dealer.dealer1go()

print("Player1 cards: ", player1.cards)
#card.totalScore("Y")
deck.aceOption(player1.cards, dealer.cards2)

print("Dealers cards: ", dealer.cards2)
#card.totalScore("N")
deck.aceOption(player1.cards, dealer.cards2)

deck.nextOption()



card()

totalScore(self) 函数和 aceOption(self) 函数不起作用，我一直对如何 link 它们感到困惑。目前正在学习如何使用类和 (self)。

此时的输出只是随机发给玩家 1 和庄家的 2 张牌，然后放在一个数组中。我需要给用户一个选项，让他们选择一张 A，如果他们有的话，是 11 还是 1。

而且我需要卡片值的总分，如果 totalScore >21 则它们 BUST 并且游戏结束。

Answer 1

由于您是 A-Level 学生，因此我们在回答您的问题时必须考虑到这一点。当您在第 7 行写 "randNum = random.randint(0, len(cardNum) - 1)" 时，您将卡片选择限制为 12 张，而不是每套 13 张。这将为您留下 48 张卡片，如 Lee Daniel Crocker 提到但并未实际解释的那样。您还可以为用户提供更改 ace 的选项，如果这是您想要执行的操作，因为这是您的代码，但您可以将其保留到最后以简化操作。

二十一点，python

Blackjack, python

blackjack

python-3.6