将分钟递增到最近的 15 分钟间隔

Increment minute to the nearest 15 minute interval

我想我快到了 - 尝试获取当前时间然后添加一个小时然后将选项输出为 15 分钟的间隔 - 所以如果它是 14:12 第一个可用的时间段将是 14:15 然后每 15 分钟一次,直到我结束时间

$start  = new DateTime("Now");
$start->add(new DateInterval('PT1H'));

$end          = new DateTime("2015-05-16 17:00");
$interval     = new DateInterval('PT15M');
$period       = new DatePeriod($start, $interval, $end);
$current_date = date('d-M-Y g:i:s A');
$current_time = strtotime($current_date);


foreach ($period as $dt)
{
    echo $dt->format('H:i')."<br>";
}

我假设你的问题是如何到达正确的第 15 分钟?

这是否解决了您的问题?:

<?php

$start          = new DateTime("Now");
$currentMinutes = $start->format('i');

if ($currentMinutes > 15) {
    $start->setTime(($start->format('H') + 1), 15);
} elseif($currentMinutes < 15) {
    $start->setTime($start->format('H'), 15);
}

$end          = new DateTime("2015-05-16 17:00");
$interval     = new DateInterval('PT15M');
$period       = new DatePeriod($start, $interval, $end);
$current_date = date('d-M-Y g:i:s A');
$current_time = strtotime($current_date);


foreach ($period as $dt)
{
    echo $dt->format('H:i')."<br>";
}

或者,如果你喜欢简短的话:

$start          = new DateTime("2015-05-16 13:15");
$currentMinutes = $start->format('i');
$currentHour    = $start->format('H');
$start->setTime(($currentMinutes > 15 ? ++$currentHour : $currentHour), 15);
[...]
$min15InSecs = 15*60;
$min15 = time()-(time()%$min15InSecs)+$min15InSecs;

$start  = new DateTime(date("Y-m-d H:i", $min15));
$start->add(new DateInterval('PT1H'));

$end  = new DateTime("2015-05-16 19:00");
$interval = new DateInterval('PT15M');
$period   = new DatePeriod($start, $interval, $end);
$current_date = date('d-M-Y g:i:s A');
$current_time = strtotime($current_date);


foreach ($period as $dt)
{

    echo $dt->format('H:i')."<br>";
}   

您可以像这样将数字限制在下一个 15 的倍数:

ceil($num / 15) * 15

如上所述调整 $start 日期。示例:

$start   = new DateTime("today 14:12"); // 2015-05-16 14:12:00
$hour    = (int) $start->format("H");   // 14
$minute  = (int) $start->format("i");   // 12
$clamped = ceil($minute / 15) * 15;     // 15
$start->setTime($hour, $clamped);       // 2015-05-16 14:15:00

setTime 注意:超出范围的值会添加到它们的父值中。