字符串集的 UITextChecker - Swift 4.2

Question

我目前有这个 Extension 感谢@Leo Dabus。它非常适合单个 String，但我如何将相同的逻辑实现到 Strings 的 Set，如 var mySet = ["word", "notaword", "stillnotaword"]。在此示例中，我希望该函数仅将第一个 index 识别为 true（即英文单词）。

extension String {
    public mutating func isEnglishWord() -> Bool {
        return UITextChecker().rangeOfMisspelledWord(in: self, range: NSRange(location: 0, length: utf16.count), startingAt: 0, wrap: false, language: "en_US").location == NSNotFound
    }
}

var myString = "word"

myString.isEnglishWord()

Answer 1

let words = ["word", "notaword", "stillnotaword"]

let validWords = words.filter { word -> Bool in
    return word.isEnglishWord()
}

let wordsArray : NSArray = NSArray(array: words)
let validWordsIndexes = wordsArray.indexesOfObjects { (word, index, _) -> Bool in
    return (word as! String).isEnglishWord()
}

print(validWords)
print(validWordsIndexes)

extension String {
    public func isEnglishWord() -> Bool {
        return UITextChecker().rangeOfMisspelledWord(in: self, range: NSRange(location: 0, length: utf16.count), startingAt: 0, wrap: false, language: "en_US").location == NSNotFound
    }
}

我添加了打印有效词和有效词索引的代码。您可以选择适合您的。谢谢

字符串集的 UITextChecker - Swift 4.2

UITextChecker for Set of Strings - Swift 4.2

string

set

uitextchecker

swift4.2