如何在 symfony 中将数据插入两个 table 具有单一表单类型？

Question

我有一个表格可以在以下 table:

中插入数据

供应商
1. first_name
2. last_name
3. 地址
地址
1. 地址
2. 城市
3. 状态
4. 密码
5. 国家

注意：我没有在供应商 table 中创建地址作为 FK，但它确实保存了地址 table 的 ID。

我参考文档做了这个表格class： https://symfony.com/doc/current/form/embedded.html

VendorType 表单 class：

class VendorType extends AbstractType {
     public function buildForm(FormBuilderInterface $builder, array $options)  
     {  
         $builder
             ->add('first_name',TextType::class,[
                 'attr' => [
                     'placeholder' => 'Enter First name',
                 ]
             ])  
             ->add('last_name',TextType::class,[
                 'attr' => [
                     'placeholder' => 'Enter Last name'
                 ]
             ])  
             ->add('address',TextAreaType::class,[
                 'attr' => [
                     'placeholder' => 'Enter your current address'
                 ],
                 'mapped' => false,
                 //if given then value wont be fetched for address in entity object.
             ])  
             ->add('city',TextType::class,[
                 'attr' => [
                     'placeholder' => 'Enter city'
                 ]
             ])  
             ->add('state',TextType::class,[
                 'attr' => [
                     'placeholder' => 'Enter state'
                 ]
             ])  
             ->add('country',TextType::class,[
                 'attr' => [
                     'placeholder' => 'Enter country'
                 ]
             ])  
             ->add('pincode',TextType::class,[
                 'attr' => [
                     'placeholder' => 'Enter Pincode'
                 ]
             ])  
             ->add('Save',SubmitType::class,[
                 'attr' => [
                     'class' => 'btn btn-success'
                 ]
             ])  

         ;  
     }  

     public function configureOptions(OptionsResolver $resolver)  
     {  
         $resolver->setDefaults([
             'data_class' => Vendor::class,
         ]);
     }  

Controller:  

$vendor = new Vendor();  
        $manager = $this->getDoctrine()->getManager();  
        $vendorForm = $this->createForm(VendorType::class, $vendor);  

        $vendorForm->handleRequest($request);  

        if ($vendorForm->isSubmitted()) {
            if ($vendorForm->isValid()) {
                $address = new Address;

                $address->setAddress($request->request->get('vendor')['address']);
                $address->setCity($request->request->get('vendor')['city']);
                $address->setState($request->request->get('vendor')['state']);
                $address->setCountry($request->request->get('vendor')['country']);
                $address->setPincode($request->request->get('vendor')['pincode']);


                $manager->persist($address);
                $manager->flush();
                if(null != $address->getId()){

                    $vendor->setFirstName($request->request->get('vendor')['first_name']);

                    $vendor->setLastName($request->request->get('vendor')['last_name']);

                    $vendor->setAddress($address->getId());
                    // dump($ven);
                    // die('uygyu');
                    $manager->persist($vendor);

                    $manager->flush();

                    $this->addFlash('success', 'Article Created! Knowledge is power!');
                }     
            }

注：在地址 table 中插入成功，但由于以下错误，数据未插入供应商 table。

错误信息： 执行 'INSERT INTO vendor (first_name, last_name, address, city, state, country, pincode) VALUES (?, ?, ?, ?, ?, ?, ?)' with params ["miss", "Negi", 62, null, null, null, null] 时发生异常：

SQLSTATE[42S22]：未找到列：1054 'field list'

中的未知列 'city'

如何将我的表单数据提交到各自的 table 中？

编辑：我知道供应商对象具有所有属性，因此它无法执行查询。我想知道这种情况如何解决？这里还能做什么？有没有更好的方法来保存这种形式？

地址实体：

namespace App\Entity;


/**
 * @ORM\Entity(repositoryClass="App\Repository\AddressRepository")
 */
class Address
{
    /**
     * @ORM\Id()
     * @ORM\GeneratedValue()
     * @ORM\Column(type="integer")
     */
    private $id;

    /**
     * @ORM\Column(type="text")
     */
    private $address;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $city;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $state;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $country;

    /**
     * @ORM\Column(type="integer")
     */
    private $pincode;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $address_type;

    /**
     * @ORM\OneToMany(targetEntity="App\Entity\Customer", mappedBy="address")
     */
    private $customers;

    public function __construct()
    {
        $this->customers = new ArrayCollection();
    }

    public function getId(): ?int
    {
        return $this->id;
    }

    public function getAddress(): ?string
    {
        return $this->address;
    }

    public function setAddress(string $address): self
    {
        $this->address = $address;

        return $this;
    }

    public function getCity(): ?string
    {
        return $this->city;
    }

    public function setCity(string $city): self
    {
        $this->city = $city;

        return $this;
    }

    public function getState(): ?string
    {
        return $this->state;
    }

    public function setState(string $state): self
    {
        $this->state = $state;

        return $this;
    }

    public function getCountry(): ?string
    {
        return $this->country;
    }

    public function setCountry(string $country): self
    {
        $this->country = $country;

        return $this;
    }

    public function getPincode(): ?int
    {
        return $this->pincode;
    }

    public function setPincode(int $pincode): self
    {
        $this->pincode = $pincode;

        return $this;
    }

    public function getAddressType(): ?string
    {
        return $this->address_type;
    }

    public function setAddressType(string $address_type): self
    {
        $this->address_type = $address_type;

        return $this;
    }

    /**
     * @return Collection|Customer[]
     */
    public function getCustomers(): Collection
    {
        return $this->customers;
    }

    public function addCustomer(Customer $customer): self
    {
        if (!$this->customers->contains($customer)) {
            $this->customers[] = $customer;
            $customer->setAddress($this);
        }

        return $this;
    }

    public function removeCustomer(Customer $customer): self
    {
        if ($this->customers->contains($customer)) {
            $this->customers->removeElement($customer);
            // set the owning side to null (unless already changed)
            if ($customer->getAddress() === $this) {
                $customer->setAddress(null);
            }
        }

        return $this;
    }
}

供应商实体：

namespace App\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity(repositoryClass="App\Repository\VendorRepository")
 */
class Vendor
{
    /**
     * @ORM\Id()
     * @ORM\GeneratedValue()
     * @ORM\Column(type="integer")
     */
    private $id;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $first_name;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $last_name;

   /**
     * @ORM\Column(type="integer")
     */
    private $address;

    /**
     * @ORM\Column(type="string", length=255)
     */
    public $city;

    /**
     * @ORM\Column(type="string", length=255)
     */
    public $state;

    /**
     * @ORM\Column(type="string", length=255)
     */
    public $country;

    /**
     * @ORM\Column(type="integer", length=255)
     */
    public $pincode;

    public function getId(): ?int
    {
        return $this->id;
    }

    public function getFirstName(): ?string
    {
        return $this->first_name;
    }

    public function setFirstName(string $first_name): self
    {
        $this->first_name = $first_name;

        return $this;
    }

    public function getLastName(): ?string
    {
        return $this->last_name;
    }

    public function setLastName(string $last_name): self
    {
        $this->last_name = $last_name;

        return $this;
    }

    public function getAddress(): ?int
    {
        return $this->address;
    }

    public function setAddress(int $address): self
    {
        $this->address = $address;

        return $this;
    }

    public function getCity(): ?string
    {
        return $this->city;
    }

    public function getState(): ?string
    {
        return $this->state;
    }

    public function getCountry(): ?string
    {
        return $this->country;
    }

    public function getPincode(): ?int
    {
        return $this->pincode;
    }
}

Answer 1

Error message: An exception occurred while executing 'INSERT INTO vendor (first_name, last_name, address, city, state, country, pincode) VALUES (?, ?, ?, ?, ?, ?, ?)' with params ["miss", "Negi", 62, null, null, null, null]

检查你的 Getters 和 Setters。在这种情况下，您没有 setter 城市属性（以及更多）。这就是 Symfony 无法在 bbdd 中插入这些属性的原因。

public function getCity(): ?string
{
    return $this->city;
}

public function setCity(string $city): self
{
    $this->city = $city;

    return $this;
}

public function getState(): ?string
{
    return $this->state;
}

public function setState(string $state): self
{
    $this->state = $state;

    return $this;
}

public function getCountry(): ?string
{
    return $this->country;
}

public function setCountry(string $country): self
{
    $this->country = $country;

    return $this;
}

public function getPincode(): ?int
{
    return $this->pincode;
}

public function setPincode(int $pincode): self
{
    $this->pincode = $pincode;

    return $this;
}

还有一件事。您在 ventor 实体中的 pincode 的 ORM 注释中有错误。它是 int 并且您正在指定字符串的长度。

/**
 * @ORM\Column(type="integer", length=255)
 */
public $pincode;

Answer 2

正如我们在提供的屏幕截图中看到的，Vendor table 中只有三个字段。有一个简单的错误，class 形式没有正确嵌入，这不是将一种形式嵌入到另一种形式的方法。 这个概念是创建 2 种不同的形式并将一种嵌入另一种。这里我们将 AddressType 形式 class 嵌入到 VendorType 形式 class.

VendorType 形式 class:

class VendorType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('first_name',TextType::class,[
                'attr' => [
                    'placeholder' => 'Enter First name',
                ]
            ])
            ->add('last_name',TextType::class,[
                'attr' => [
                    'placeholder' => 'Enter Last name'
                ]
            ])
            //Embeding AddressType form in VendorType form.
            ->add('address', AddressType::class)
            ->add('Save',SubmitType::class,[
                'attr' => [
                    'class' => 'btn btn-success'
                ]
            ])

        ;
    }

注意：在上面的代码中查找注释。

如何在 symfony 中将数据插入两个 table 具有单一表单类型？

How to insert data into two table have a single form type in symfony?

php

database

forms

symfony

symfony-4.2