合并两个列表的每个项目 separet.py

Question

我试图寻找答案，但找不到。

我有两个列表。两个列表都有 71 项。

我希望合并两个列表中的每个索引。

These two list that I want to combine
This is what I get but it is not what I want
This is the result that I want

Answer 1

你可以这样做：

extensions =['.sp1', '.sp1', '.sp2']
my_numbers =[4, 16, 128]
new_list = []

for x in range(len(my_numbers)):
    new_list.append("".join([str(my_numbers[x]), extensions[x]]))

print(new_list)

输出：

['4.sp1', '16.sp1', '128.sp2']

合并两个列表的每个项目 separet.py

combinding each items for both list separet.py

python

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