namedtuple：预期 1 个参数，得到 3 个

Question

我有这个基本的命名元组：

from collections import namedtuple

DBInfos = namedtuple('dbname', 'dbpath', 'dbfile')

当我尝试用

实例化一个时

d = DBInfos._make(['test', 'a/b/c', '.index.db'])

我收到以下错误：

Traceback (most recent call last):
 File "./test.py", line 5, in <module>
 d = DBInfos._make(['test', 'a/b/c', '.index.db'])
 File "<string>", line 21, in _make
TypeError: Expected 1 arguments, got 3

但我不知道为什么:/

Answer 1

您对 namedtuple 函数的调用不正确。应该是：

DBInfos = namedtuple('DBInfos', ['dbname', 'dbpath', 'dbfile'])

参见：https://docs.python.org/2.7/library/collections.html#collections.namedtuple

namedtuple：预期 1 个参数，得到 3 个

namedtuple: expected 1 argument, got 3

python

namedtuple