来自 Mysql DB C# 的旋转块引用

Question

这是我的数据库

CREATE TABLE IF NOT EXISTS `comments` (
  `com_id` int(11) NOT NULL AUTO_INCREMENT,
  `com_name` varchar(500) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
  `com_content` text CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
  `com_website` varchar(500) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
  `com_date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  PRIMARY KEY (`com_id`)
)

这是我的前端

<link href="js/jquery.bxslider.css" rel="stylesheet" type="text/css" />
 <div class="container">
    <asp:Label ID="lblComment" runat="server" Text=""/>
</div>
<script src="js/jquery.bxslider.min.js" type="text/javascript"></script>
<script type="text/javascript">
    $(document).ready(function () {
        $('.bxslider').bxSlider({
            mode: 'horizontal',
            slideMargin: 3,
            auto: true
        });
    });
</script>

最后是我的后端

private void dispComments()
{
    using (MySqlConnection conn = new MySqlConnection("server=localhost;database=test;uid=root;password="))
    {
        string query = "select * from comments order by com_date desc";
        DataTable dt = new DataTable();

        using (MySqlDataAdapter da = new MySqlDataAdapter(query, conn))
        {
            da.Fill(dt);

            string comment = null;

            for (int i = 0; i < dt.Rows.Count; i++)
            {
                //Message title
                //news += "<div class='page-header' style='text-transform:capitalize;'><small>";
                //news += dt.Rows[i]["com_content"].ToString();
                //news +="</small></div>";

                //Message Body
                comment += "<ul class='bxslider'>";
                comment += "<li>";
                comment += "<blockquote>";
                comment += dt.Rows[i]["com_content"].ToString();
                comment += "<p style='text-align: right; margin-right: 20px;'>";
                comment += dt.Rows[i]["com_name"].ToString();
                comment += "</p></blockquote>";
                comment += "</li>";
                comment += "</ul>";

            }
            lblComment.Text = comment;
        }
    }
}

...我对我的评论有 3 条评论 table，所有这三个都已显示并且输出很好，除了它们往往单独出现，每次旋转只显示一个评论。我哪里出错了？请帮忙！！

Answer 1

<ul> 应该在 for 循环之外。当前代码在每次迭代下创建一个新的 <ul>。所以对于每个 li 你有一个 ul，并且对于每个 ul 滑块被初始化。

修改为这段代码，

string comment = null;
comment += "<ul class='bxslider'>";
for (int i = 0; i < dt.Rows.Count; i++)
{
    comment += "<li>";
    ....
    comment += "</li>";
}
comment += "</ul>";

来自 Mysql DB C# 的旋转块引用

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c#

jquery

mysql

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