Kendo UI 下拉列表未显示正确的值
Kendo UI Dropdownlist not display correct value
我遇到过这样的情况,我的下拉列表应该根据我的 userPropertyID=3
显示 GUEST HOUSE,但不知何故它仍然没有在下拉列表中显示正确的值。需要您的帮助,感谢您的宝贵时间。
var userPropertyID = 3;
var propertyTBL = [
{"propertyID":"1","propertyName":"HOTEL"},
{"propertyID":"2","propertyName":"RESORT"},
{"propertyID":"3","propertyName":"GUEST HOUSE"},
{"propertyID":"4","propertyName":"HOME"},
{"propertyID":"5","propertyName":"MOTEL"}];
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL
});
dropdownlist.select(userPropertyID);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled</title>
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.common.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.mobile.min.css" />
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/jquery.min.js"></script>
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/kendo.all.min.js"></script>
<style>*{font-family:Arial;font-size:11px;}</style>
<body>
Property Name:<input id="dropdownlist"/>
</body>
</html>
发生这种情况是因为您没有将正确的 kendo 小部件分配给变量。所以它不知道kendo的函数。
正确的方法是这样(通过使用 .data('kendoDropDownList'))
var dropdownlist = $("#dropdownlist").data('kendoDropDownList');
所以在你的情况下,你需要将你的代码部分更改为这个。
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL
}).data('kendoDropDownList');
但请记住,索引从 0 开始(我在您的代码中看到,在索引 3 处,您再次拥有与索引 0 处一样的 HOME 值,所以不要对此感到困惑)。
现在调用 .value() 函数就可以了
dropdownlist.select(userPropertyID - 1);
最后,如果您在创建小部件后立即设置值,即使在您的实际应用程序中,您也可以使用 value 属性 来设置它
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL,
value: userPropertyID
}).data('kendoDropDownList');
编辑:为了使其完整,这里是您修改后的代码片段
var userPropertyID = 3;
var propertyTBL = [
{"propertyID":"1","propertyName":"HOTEL"},
{"propertyID":"2","propertyName":"RESORT"},
{"propertyID":"3","propertyName":"GUEST HOUSE"},
{"propertyID":"4","propertyName":"HOME"},
{"propertyID":"5","propertyName":"MOTEL"}];
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL
}).data('kendoDropDownList');
dropdownlist.select(userPropertyID - 1);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled</title>
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.common.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.mobile.min.css" />
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/jquery.min.js"></script>
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/kendo.all.min.js"></script>
<style>*{font-family:Arial;font-size:11px;}</style>
<body>
Property Name:<input id="dropdownlist"/>
</body>
</html>
我遇到过这样的情况,我的下拉列表应该根据我的 userPropertyID=3
显示 GUEST HOUSE,但不知何故它仍然没有在下拉列表中显示正确的值。需要您的帮助,感谢您的宝贵时间。
var userPropertyID = 3;
var propertyTBL = [
{"propertyID":"1","propertyName":"HOTEL"},
{"propertyID":"2","propertyName":"RESORT"},
{"propertyID":"3","propertyName":"GUEST HOUSE"},
{"propertyID":"4","propertyName":"HOME"},
{"propertyID":"5","propertyName":"MOTEL"}];
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL
});
dropdownlist.select(userPropertyID);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled</title>
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.common.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.mobile.min.css" />
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/jquery.min.js"></script>
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/kendo.all.min.js"></script>
<style>*{font-family:Arial;font-size:11px;}</style>
<body>
Property Name:<input id="dropdownlist"/>
</body>
</html>
发生这种情况是因为您没有将正确的 kendo 小部件分配给变量。所以它不知道kendo的函数。
正确的方法是这样(通过使用 .data('kendoDropDownList'))
var dropdownlist = $("#dropdownlist").data('kendoDropDownList');
所以在你的情况下,你需要将你的代码部分更改为这个。
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL
}).data('kendoDropDownList');
但请记住,索引从 0 开始(我在您的代码中看到,在索引 3 处,您再次拥有与索引 0 处一样的 HOME 值,所以不要对此感到困惑)。
现在调用 .value() 函数就可以了
dropdownlist.select(userPropertyID - 1);
最后,如果您在创建小部件后立即设置值,即使在您的实际应用程序中,您也可以使用 value 属性 来设置它
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL,
value: userPropertyID
}).data('kendoDropDownList');
编辑:为了使其完整,这里是您修改后的代码片段
var userPropertyID = 3;
var propertyTBL = [
{"propertyID":"1","propertyName":"HOTEL"},
{"propertyID":"2","propertyName":"RESORT"},
{"propertyID":"3","propertyName":"GUEST HOUSE"},
{"propertyID":"4","propertyName":"HOME"},
{"propertyID":"5","propertyName":"MOTEL"}];
var dropdownlist = $("#dropdownlist").kendoDropDownList({
dataTextField: "propertyName",
dataValueField: "propertyID",
dataSource: propertyTBL
}).data('kendoDropDownList');
dropdownlist.select(userPropertyID - 1);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled</title>
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.common.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.min.css" />
<link rel="stylesheet" href="https://kendo.cdn.telerik.com/2019.1.115/styles/kendo.silver.mobile.min.css" />
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/jquery.min.js"></script>
<script src="https://kendo.cdn.telerik.com/2019.1.115/js/kendo.all.min.js"></script>
<style>*{font-family:Arial;font-size:11px;}</style>
<body>
Property Name:<input id="dropdownlist"/>
</body>
</html>