将 curl get to rest api 转换为 python

Question

我有这个 curl 命令：

curl -X GET --header 'Accept: application/vnd.pagerduty+json;version=2' --header 'Authorization: Token token=y_NbAkKc66ryYTWUXYEu' 'https://api.pagerduty.com/services?time_zone=UTC&sort_by=name'

我需要使用 requests 库将其转换为 python

import requests

def support(self): 
    services_list = requests.get('I need to convert the link to pass it here as a parameter')

Answer 1

import requests

def support():
    headers = {
        'Accept': 'application/vnd.pagerduty+json;version=2',
        'Authorization': 'Token token=y_NbAkKc66ryYTWUXYEu'}

    payloads = (
        ('time_zone', 'UTC'),
        ('sort_by', 'name'),)

    services_list = requests.get('https://api.pagerduty.com/services', headers=headers, params=payloads)

将 curl get to rest api 转换为 python

convert curl get to rest api to python

python

python-3.x

python-requests

pagerduty