IBM SQL 求和和分组依据

Question

我正在尝试进行联接并获取采购订单中行项目的总数。它是网页上的网格。我正在显示 PO 的所有信息，但我还想要每个 PO 的每行项目的总美元。

我收到以下错误消息：

SQL0122 SELECT 列表中的列或表达式无效。

我不确定我做错了什么？

Tables:

Table @HPO (PO):

PO#   Vendor  Status
123   aaa     Approved
321   bbb     Approved
456   ccc     Pending
654   ddd     Draft

Table HPO（采购订单中的行项目）：

PO#  Total Price
123  100.00
123  25.00
321  75.00
456  25.00
654  10.00
654  90.00

Table AVM（供应商）：

Vendor Vendor#
aaa     444
bbb     555
ccc     777

这是我的代码：

    EXEC SQL Declare RSCURSOR1 cursor for
          SELECT A.*, B.*, SUM(C.PECST) as POTOTAL
          FROM @HPO A
          INNER JOIN AVM B on A.HPOVNO = B.VENDOR
          INNER JOIN HPO C on A.HPOORD = C.PORD
          GROUP BY C.PORD
          ORDER BY HPOORD DESC

          OFFSET (:StartingRow - 1) * :NbrOfRows ROWS
          FETCH NEXT :NbrOfRows + 1 ROWS ONLY;

          EXEC SQL  Open RSCURSOR1;

          EXEC SQL SET RESULT SETS Cursor RSCURSOR1;  

Update code:

EXEC SQL Declare RSCURSOR1 cursor for
      SELECT A.HPOORD, A.HPORNB, A.HPORBY, A.HPODTO, A.HPOSTS, A.HPOVNO, A.HPOURG, B.VNDNAM, SUM(C.PECST) as POTOTAL
      FROM @HPO A
      INNER JOIN AVM B on A.HPOVNO = B.VENDOR
      INNER JOIN HPO C on A.HPOORD = C.PORD
      GROUP BY A.HPOORD, A.HPORNB, A.HPORBY, A.HPODTO, A.HPOSTS, A.HPOVNO, A.HPOURG, B.VNDNAM, C.PECST
      ORDER BY HPOORD DESC

      OFFSET (:StartingRow - 1) * :NbrOfRows ROWS
      FETCH NEXT :NbrOfRows + 1 ROWS ONLY;

      EXEC SQL  Open RSCURSOR1;

      EXEC SQL SET RESULT SETS Cursor RSCURSOR1;

Answer 1

在 select 列表和 group by 子句中指定列名

DEMO

SELECT A.PO#,Vendor,Status, SUM(C.PECST) as POTOTAL
      FROM @HPO A
      INNER JOIN AVM B on A.HPOVNO = B.VENDOR
      INNER JOIN HPO C on A.HPOORD = C.PORD
      GROUP BY A.PO#,Vendor,Status
      ORDER BY HPOORD DESC

根据您的代码 - 从 group by

中删除 C.PECST

SELECT A.HPOORD, A.HPORNB, A.HPORBY, A.HPODTO, A.HPOSTS, A.HPOVNO, A.HPOURG, B.VNDNAM, SUM(C.PECST) as POTOTAL
      FROM @HPO A
      INNER JOIN AVM B on A.HPOVNO = B.VENDOR
      INNER JOIN HPO C on A.HPOORD = C.PORD
      GROUP BY A.HPOORD, A.HPORNB, A.HPORBY, A.HPODTO, A.HPOSTS, A.HPOVNO, A.HPOURG, B.VNDNAM
      ORDER BY HPOORD DESC

IBM SQL 求和和分组依据

IBM SQL Sum and Group By

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