条件格式化文本框

Conditional Formatting a textbox

我正在使用 ReportBuilder

下面是根据单元格中的值更改背景颜色的表达式。我想向现有表达式添加一个新条件,以将文本框 22 中的 'N/A' 更改为浅绿色

=iif(isnothing(reportitems!Textbox22.value),Nothing, switch(reportitems!Textbox22.value >1 and reportitems!Textbox22.value <=50,"#fd6767",reportitems!Textbox22.value >=51 and reportitems!Textbox22.value <=79,"#f8d3a9",reportitems!Textbox22.value >=80 and reportitems!Textbox22.value <=100,"LightGreen",reportitems!Textbox22.value = 0, "#fd6767"))

这是设计图

这是单元格中的表达式,如果该单元格没有值,它会返回 "N/A"。

=iif(isnothing(lookup(Fields!StatID.value,Fields!statID.value,Fields!pass_rate.value,"Res2nd")),"N/A",lookup(Fields!StatID.value,Fields!statID.value,Fields!pass_rate.value,"Res2nd"))

这是输出

我试过下面的方法,但这会使所有单元格变白

 =switch(reportitems!Textbox22.value >1 and reportitems!Textbox22.value <=50,"#fd6767",reportitems!Textbox22.value >=51 and reportitems!Textbox22.value <=79,"#f8d3a9",reportitems!Textbox22.value >=80 and reportitems!Textbox22.value <=100,"LightGreen",reportitems!Textbox22.value = 0, "#fd6767",reportitems!Textbox22.value = "N/A","LightGreen")

将你的表达修改为:

=iif(isnothing(reportitems!Textbox22.value),Nothing, switch(reportitems!Textbox22.value >1 and reportitems!Textbox22.value <=50,"#fd6767",reportitems!Textbox22.value >=51 and reportitems!Textbox22.value <=79,"#f8d3a9",reportitems!Textbox22.value >=80 and reportitems!Textbox22.value <=100,"LightGreen",reportitems!Textbox22.value = 0, "#fd6767",reportitems!Textbox22.value ="N/A","LightGreen"))

试试这个表达式:

=switch(reportitems!Textbox22.value >=0 and reportitems!Textbox22.value <=50,"#fd6767",reportitems!Textbox22.value >=51 and reportitems!Textbox22.value <= 79,"#f8d3a9",reportitems!Textbox22.value >=80 or reportitems!Textbox22.value  = "N/A","LightGreen")

通过使用下面的

设法使这个最终工作
=iif(reportitems!Textbox22.value >=0 and reportitems!Textbox22.value <=50 ,"#f1b1b1",iif(reportitems!Textbox22.value >50 and reportitems!Textbox22.value <=79,"#f8d3a9","LightGreen"))