改变 OpenLayers 集群特征的风格
Changing style in OpenLayers clustered features
我正在将 OpenLayers 与 Javascript 结合使用,并在地图上显示集群特征。我想根据其属性值之一更改集群内功能的图标。
var style1 = new ol.style.Icon(/** @type {olx.style.IconOptions} */ ({
anchor: [0.5, 66],anchorXUnits: 'fraction',anchorYUnits: 'pixels',
opacity: 0.85,src: 'https://img.icons8.com/flat_round/64/000000/home.png',scale: 0.3
}));
var style2 = new ol.style.Icon(/** @type {olx.style.IconOptions} */ ({
anchor: [0.5, 66],anchorXUnits: 'fraction',anchorYUnits: 'pixels',
opacity: 0.85,src: 'https://img.icons8.com/color/48/000000/summer.png',scale: 0.3
}));
function myStyleFunction(feature) {
let props = feature.getProperties();
if (props.id>50) {
console.log(props.id);
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
console.log(props.id);
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};
在上面的代码中,我想访问集群中其中一项功能的 属性 "id" 并根据 "id" 值设置其图标。但是,我无法获得 属性.
功能
这是一个codepen。我将不胜感激任何人的帮助。
如果您只检查每个集群中的第一个特征:
function myStyleFunction(feature) {
let props = feature.get('features')[0].getProperties();
if (props.id>50) {
console.log(props.id);
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
console.log(props.id);
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};
如果你想在集群中的任何特征中找到值
function myStyleFunction(feature) {
let maxId = 0;
feature.get('features').forEach(function(feature){
maxId = Math.max(maxId, feature.getProperties().id);
});
if (maxId>50) {
console.log(maxId);
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
console.log(maxId);
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};
对于 ol-ext 集群
function myStyleFunction(feature) {
let id = 0;
let features = feature.get('features');
if (features) {
id = features[0].get('id');
}
if (id > 50) {
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};
我正在将 OpenLayers 与 Javascript 结合使用,并在地图上显示集群特征。我想根据其属性值之一更改集群内功能的图标。
var style1 = new ol.style.Icon(/** @type {olx.style.IconOptions} */ ({
anchor: [0.5, 66],anchorXUnits: 'fraction',anchorYUnits: 'pixels',
opacity: 0.85,src: 'https://img.icons8.com/flat_round/64/000000/home.png',scale: 0.3
}));
var style2 = new ol.style.Icon(/** @type {olx.style.IconOptions} */ ({
anchor: [0.5, 66],anchorXUnits: 'fraction',anchorYUnits: 'pixels',
opacity: 0.85,src: 'https://img.icons8.com/color/48/000000/summer.png',scale: 0.3
}));
function myStyleFunction(feature) {
let props = feature.getProperties();
if (props.id>50) {
console.log(props.id);
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
console.log(props.id);
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};
在上面的代码中,我想访问集群中其中一项功能的 属性 "id" 并根据 "id" 值设置其图标。但是,我无法获得 属性.
功能这是一个codepen。我将不胜感激任何人的帮助。
如果您只检查每个集群中的第一个特征:
function myStyleFunction(feature) {
let props = feature.get('features')[0].getProperties();
if (props.id>50) {
console.log(props.id);
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
console.log(props.id);
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};
如果你想在集群中的任何特征中找到值
function myStyleFunction(feature) {
let maxId = 0;
feature.get('features').forEach(function(feature){
maxId = Math.max(maxId, feature.getProperties().id);
});
if (maxId>50) {
console.log(maxId);
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
console.log(maxId);
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};
对于 ol-ext 集群
function myStyleFunction(feature) {
let id = 0;
let features = feature.get('features');
if (features) {
id = features[0].get('id');
}
if (id > 50) {
return new ol.style.Style({image: style1,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
} else {
return new ol.style.Style({image: style2,stroke: new ol.style.Stroke({ color:"#fff", width:1 }) });
}
};