如何将总和转换为时间 - mysql

Question

我在 mysql 数据库中创建了 "leave" table:

+--------+---------+---------+-------------+---------+-------------------------------+
|ID_LEAVE|ID_WORKER| FNAME | LNAME | BEGIN_DATE         | END_DATE             | 
+--------+---------+---------+---------+------------+--------------------+-----------
| 1      |   1     | ALAN  | MAX  |2019-03-19 07:00:00 |2019-03-20 15:00:00   | 
| 2      |   1     | ALAN  | MAX   |2019-03-21 07:00:00  |2019-03-21 15:00:00    |
+--------+---------+---------+----------------------+--------------------------------+

"Workers Table"

+----------+---------+---------+
|ID_WORKER |  FNAME  | LNAME   |
+----------+---------+----------
| 1        |  ALAN   |  MAX    |
| 2        |  MARK   |  DARK   |
+----------+---------+---------+

"Orders" Table:

+----------+--------------+---------------+
|ID_ORDER  |  DESC_ORDER  | NUMBER_ORDER  |
+----------+--------------+---------------+
| 20       |  TEST        |  TEST         |
+----------+--------------+---------------+

"Order_status" Table:

+----------+---------+---------+---------------------+-------------------+------------+
| Id_status|ID_WORKER| ID_ORDER| BEGIN_DATE          | END_DATE          | ORDER_DONE |
+----------+---------+---------+----------+------------+---------+--------------------+
| 30       |   1     |    20   |2019-03-18 06:50:35  |2019-03-18 15:21:32|  NO        |
| 31       |   1     |    20   |2019-03-20 06:44:12  |2019-03-20 15:11:23|  NO        |
| 32       |   1     |    20   |2019-03-22 06:50:20  |2019-03-22 12:22:33|  YES       |
| 33       |   2     |    20   |2019-03-18 06:45:11  |2019-03-18 15:14:45|  NO        |
| 34       |   2     |    20   |2019-03-20 06:50:22  |2019-03-20 15:10:32|  NO        |
| 35       |   2     |    20   |2019-03-22 06:54:11  |2019-03-22 11:23:45|  YES       |
+----------+---------+---------+------------+---------+-------------------+-----------+

我做了什么：

我可以汇总 "total time" 的其他工人（在 order_status table 中），包括汇总离开 table 的 "leave time"。我也正确地选择了工人（LNAME、FNAME）订单（DESC_ORDER 和 NUMBER_ORDER）和 "TOTAL TIME" 订单。我在下面写了 mysql 命令：

SELECT workers.fname, 
       workers.lname, 
       order_statusAgg.number_order,
       workers.id_worker,
       order_statusAgg.desc_order, 
       SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'TOTAL TIME', 
       IFNULL(SEC_TO_TIME(SUM(leaveAgg.vtime)),'00:00:00') AS 'LEAVE TIME'
FROM   workers 
LEFT JOIN (
SELECT leave.id_worker, time_format(SUM((datediff(leave.end_date, leave.begin_date) + 1) * (time(leave.end_date) - time(leave.begin_date))), '%H:%i:%s') AS vtime 
FROM leave
GROUP BY leave.id_worker 
) leaveAgg
               ON leaveAgg.id_worker = workers.id_worker
       LEFT JOIN (
SELECT order_status.id_worker, orders.number_order, orders.desc_order, SUM((Time_to_sec(order_status.end_date) - 
                       Time_to_sec(order_status.begin_date))) AS stime
FROM order_status
           INNER JOIN orders 
               ON orders.id_order = order_status.id_order
GROUP BY order_status.id_worker
) order_statusAgg
               ON workers.id_worker = order_statusAgg.id_worker 

WHERE  order_statusAgg.number_order LIKE 'TEST'
GROUP BY workers.id_worker

然后我得到结果：

    +---------+---------+---------------+------------+------------+--------------+
    |  FNAME  | LNAME   |  NUMBER_ORDER | DESC_ORDER | TOTAL TIME | LEAVE_TIME   | 
    +---------+---------+---------------+------------+------------+--------------+
    |  ALAN   |  MARK   | TEST          | TEST       | 22:30:21   |00:00:24.000000|   
    +---------+---------+---------------+------------+------------+--------------+
    |  MARK   |  GREEN  | TEST          | TEST       | 21:19:18   |   00:00:00    |   
    +---------+---------+---------------+------------+------------+--------------+

但是关于休假时间是不正确的，因为当我写那个命令时：

    SELECT leave.id_worker, 
time_format(SUM((datediff(leave.end_date, leave.begin_date) + 1) * (time(leave.end_date) - time(leave.begin_date))), '%H:%i:%s') AS vtime 
    FROM leave
    GROUP BY leave.id_worker

+----------+---------+
|ID_WORKER |  vtime  |
+----------+---------+
| 1        | 24:00:00|
+----------+---------+

我试过这样做：

1) IFNULL(SUM(leaveAgg.vtime),'00:00:00') AS 'Leave time'
2) IFNULL(time_format(SUM(leaveAgg.vtime),'%H:%i:%s'),'00:00:00') AS 'Leave time'

但是其中 none 个没有用。

所以在这种情况下我需要将计数转换为日期时间

00:00:24.000000 => 24:00:00

我一直在寻找想法，但我还没有找到成功的解决方案。有任何想法吗？有人可以告诉我应该做什么或可以写什么样的查询吗？感谢您的帮助！

Answer 1

SELECT workers.fname, 
   workers.lname, 
   order_statusAgg.number_order,
   workers.id_worker,
   order_statusAgg.desc_order, 
   SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'TOTAL TIME', 
   IFNULL(SEC_TO_TIME(SUM(leaveAgg.vtime)),'00:00:00') AS 'LEAVE TIME'
FROM workers 
LEFT JOIN (
SELECT leave.id_worker, SUM((datediff(leave.end_date, leave.begin_date) + 1) * (time_to_sec(time(leave.end_date)) - time_to_sec(time(leave.begin_date)))) AS vtime 
FROM leave
GROUP BY leave.id_worker) leaveAgg
           ON leaveAgg.id_worker = workers.id_worker
   LEFT JOIN (
SELECT order_status.id_worker, orders.number_order, orders.desc_order, 
SUM((Time_to_sec(order_status.end_date) - 
                   Time_to_sec(order_status.begin_date))) AS stime
FROM order_status
       INNER JOIN orders 
           ON orders.id_order = order_status.id_order
GROUP BY order_status.id_worker) order_statusAgg
           ON workers.id_worker = order_statusAgg.id_worker 
WHERE  order_statusAgg.number_order LIKE 'TEST'
GROUP BY workers.id_worker;

我没有做太多，我只是改变了这部分：

SELECT leave.id_worker, time_format(SUM((datediff(leave.end_date, leave.begin_date) + 1) * (time(leave.end_date) - time(leave.begin_date))), '%H:%i:%s') AS vtime

到

SELECT leave.id_worker, SUM((datediff(leave.end_date, leave.begin_date) + 1) * (time_to_sec(time(leave.end_date)) - time_to_sec(time(leave.begin_date)))) AS vtime

在你的 leaveAgg.

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