在 ng-container 中访问子组件变量

Access child component variables within ng-container

我有一个名为 Suggestion List 的自定义组件,它向用户显示来自可观察对象的建议列表。我已经尽可能通用地创建了这个组件,这样你就可以传递任何数据数组,所以我希望能够从父级自定义它的显示,因为我永远不会确定对象会是什么样子,直到实施它。不幸的是,我无法从 ng-container 中的父组件访问子组件变量。

使用 ng-container 或 ng-template 是否可行,或者我应该完全走另一条路吗?

父组件

    <suggestion-list (suggestionSelected)="selectSuggestion($event)" [$suggestions]="$suggestionSource">
      <ng-container>
        {{suggestion.firstname + ' ' + suggestion.lastname}}
      <ng-container>
    </suggestion-list>

子组件

  <mat-list role="list">
    <mat-list-item *ngFor="let suggestion of $suggestions | async">
      <mat-icon mat-list-icon>person</mat-icon>
      <mat-card (click)="selectSuggestion(suggestion)">
        <ng-container></ng-container>
      </mat-card>
    </mat-list-item>
  </mat-list>

Here 是工作示例

parent.component.html

   <div>
     <suggestion-list (suggestionSelected)="selectSuggestion($event)" [$suggestions]="$suggestionSource">
       <p>{{suggestion.firstname + ' ' + suggestion.lastname}}</p>
     </suggestion-list>
   </div>

child.component.html

   <div>
     <ng-content></ng-content>
     <p>Hello !</p>
   </div>

一种方法是使用 ng-template。您可以在父组件中为每个元素定义一个模板,并在子组件中为数组中的每个元素显示模板:

父组件:

<suggestion-list (suggestionSelected)="selectSuggestion($event)" 
                 [suggestions]="$suggestionSource | async" 
                 [suggestionTemplate]="suggestionTemplate">
</suggestion-list>

<ng-template #suggestionTemplate let-suggestion>
<span>{{suggestion.firstname + ' ' + suggestion.lastname}}</span>
</ng-template>

并且在您的子组件中您可以这样做(请注意我们通过 ng-template:

的隐式上下文在模板中传递建议变量
<ng-container *ngFor="let suggestion of suggestions>
    <ng-container *ngTemplateOutlet="suggestionTemplate; context: {$implicit: suggestion}"></ng-container>
</ng-container>

在子组件的.ts文件中,声明传入的模板,如:

@Input() suggestionTemplate: TemplateRef<any>;

PS:这段代码是我现在写的,所以还没有测试,但我想你可以知道你能做什么!