由于两个表之间的外键约束而无法登录

Question

我有两个table'User'和'Address'，还有OneToOne 它们之间的关系，因为 用户 table 有一列 'address_id' 存储地址 table 的 'id'。

这是用户实体中的注释：

/**
     * @ORM\OneToOne(targetEntity="App\Entity\address", cascade={"persist", "remove"})
     * @ORM\JoinColumn(nullable=false)
     */
    private $address;

Security.yaml:

security:
    encoders:
        App\Entity\User:
            algorithm: bcrypt

    providers:
        my_provider:
            entity:
                class: App\Entity\User
                property: username
    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
            anonymous: true

            form_login:
                login_path: login
                check_path: login
                provider: my_provider
                default_target_path: dashboard

            logout:
                path: /logout
                target: /

    access_control:
        - { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY  }
        - { path: ^/dashboard, roles: ROLE_USER }

控制器：

namespace App\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing\Annotation\Route;
use Symfony\Component\Security\Http\Authentication\AuthenticationUtils;

class SecurityController extends AbstractController
{
    /**
     * @Route("/login", name="login")
     */
    public function login(Request $request,AuthenticationUtils $utils)
    {
        // get the login error if there is one
        $error = $utils->getLastAuthenticationError();
        // dump($error);die;

        // last username entered by the user
        $lastUsername = $utils->getLastUsername();
        return $this->render('security/login.html.twig', [
            'last_username' => $lastUsername,
            'error' => $error
            ]);
    }

    public function logout()
    {
        # code...
    }   
}

我在输入用户名和密码时出现此错误：

Authentication request could not be processed due to a system problem.

这是我在控制器中转储（）错误时得到的结果。

SecurityController.php on line 20:
AuthenticationServiceException {#189 ▼
  -token: UsernamePasswordToken {#236 ▶}
  #message: "The target-entity App\Entity\address cannot be found in 'App\Entity\User#address'."
  #code: 0
  #file: "/home/users/kumar.saurabh/www/html/symfony/test-project/vendor/symfony/security-core/Authentication/Provider/DaoAuthenticationProvider.php"
  #line: 85
  trace: {▶}
}

当我删除 $address 变量及其 getter 和 setter 函数时，登录工作正常，但是当我使用它时，出现上述错误。

如何使用外键实现此目的？我是 symfony 的新手，正在学习 4.2 版本。

Answer 1

注意大小写，将 App\Entity\address 替换为 App\Entity\Address，更新您的架构，应该没问题

/**
 * @ORM\OneToOne(targetEntity="App\Entity\address", cascade={"persist", "remove"})
 * @ORM\JoinColumn(nullable=false)
 */
private $address;

应该是

/**
 * @ORM\OneToOne(targetEntity="App\Entity\Address", cascade={"persist", "remove"})
 * @ORM\JoinColumn(nullable=false)
 */
private $address;

由于两个表之间的外键约束而无法登录

Unable to login due to Foreign key constraint between two tables

php

symfony

login

symfony-forms

symfony-4.2