Eclipselink NamedNativeQuery 将列名作为参数而不是值传递

Eclipselink NamedNativeQuery pass column name as parameter and not a value

尝试将列名作为参数传递,但 JPA 将其设置为用单引号括起来的值。

@NamedNativeQueries({
    @NamedNativeQuery(
            name = "Genre.findAllLocalized",
            query = "SELECT "
                    + " CASE "
                    + "     WHEN ? IS NULL THEN genre_default"
                    + "     ELSE ? "
                    + " END localized_genre "
                    + "FROM genre ORDER BY localized_genre")
})

然后:

List<String> res = em.createNamedQuery("Genre.findAllLocalized")
                .setParameter(1, colName)
                .setParameter(2, colName)
                .getResultList();

问题是传递的列名被视为,因此结果将return结果列表与"col_name"的重复值而不是选择作为参数传递的列的值。

这是可以实现的吗?

基本上创建这样一个准备好的查询是没有意义的,无论如何你会如何命名该查询:“*”?所以简短的回答是:不。

  1. 但是如果符合您的要求,您可以动态创建命名查询:

    String colName = "colName";
    String query = "SELECT WHEN " + colName + " IS NULL THEN genre_default";
    Query query = entitymanager.createQuery(query);
    
  2. 使用标准生成器可能更适合您使用 JPA 的方式(来自 https://en.wikibooks.org/wiki/Java_Persistence/Criteria 的代码):

    // Select the employees and the mailing addresses that have the same address.
    CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
    CriteriaQuery criteriaQuery = criteriaBuilder.createQuery();
    Root employee = criteriaQuery.from(Employee.class);
    Root address = criteriaQuery.from(MailingAddress.class);
    criteriaQuery.multiselect(employee, address);
    
    criteriaQuery.where( criteriaBuilder.equal(employee.get("address"), address.get("address"));
    Query query = entityManager.createQuery(criteriaQuery);
    List<Object[]> result = query.getResultList();