对从 RECURSIVE 查询中检索到的记录进行分组,这些记录具有相同的 parents、grandparents

Group retrieved records from a RECURSIVE query, that have the same parents, grandparents

我有一个 table 与项目的关系,而不是与类别的多对多关系。

项目

id  |  name 
 1     name1
 2     name2
 3     name3 

项目类别

id | category_id | item_id
  1     4            1
  2     5            1
  3     7            1
  4     8            1

类别(parent_id 自身的外键)

  id | parent_id | name     
   1     Null       A1
   2      1         B1
   3      1         B2 
   4      2         C1
   5      3         C2
   6      1         D1
   7      6         DE
   8      1         DT

我正在尝试获取项目的项目类别,从 child 到 parent,因此我使用:

 WITH RECURSIVE descendants(name, id, slug, parent_id, bread_order) AS (
 SELECT  name, id, slug, parent_id, 0
 FROM categories
 where id in (
 SELECT c.id FROM items AS p
 INNER JOIN items_categories AS pc ON p.id=pc.item_id 
 INNER JOIN categories AS c ON pc.category_id = c.id
     WHERE p.id = 10
 )   
 UNION ALL
 SELECT c2.name, c2.id, c2.slug, c2.parent_id, bread_order+1
 FROM categories AS c2
 INNER JOIN descendants AS d ON c2.id=d.parent_id
) SELECT id, name, parent_id, bread_order FROM descendants 
ORDER by bread_order DESC

问题是两个 child 类别可以有相同的 parent,或者一个 parent 对另一个是大 parent。

C1 -> B1 -> A1
C2 ->B1  -> A1
C3 ->B2  -> A1
DE -> D1 -> A1
DT  -> A1

我试图将它们分组但是,因为有相同的 parents,grand_parents 不是我需要的,当我从数据库中检索信息时我需要知道如何制作路径(见上文)。

有什么办法吗,比如使用 CASE 和来自子查询的 returns 的 ID?

查询时可以聚合路径:

WITH RECURSIVE descendants(name, id, parent_id, bread_order, path) AS (
  SELECT  name, id, parent_id, 0, array[id] as path
  FROM categories
  where id in (SELECT c.id
               FROM items AS p
                 JOIN items_categories AS pc ON p.id=pc.item_id 
                 JOIN categories AS c ON pc.category_id = c.id
               WHERE p.id = 1)   
  UNION ALL

  SELECT c2.name, c2.id, c2.parent_id, bread_order+1, d.path||c2.id
  FROM categories AS c2
    JOIN descendants AS d ON c2.id=d.parent_id
) 
SELECT id, name, parent_id, path, bread_order
FROM descendants 
ORDER by path