如何在 UIPickerView 中显示需要的行？

Question

我知道数组中的数据，我需要在我的应用程序加载时显示 selected 行。我怎样才能select"Four"，比如在开头？

enter image description here

let arrayOfNumbers = ["One", "Two", "Three", "Four", "Five"]

override func viewDidLoad() {
    super.viewDidLoad()
    pickerTest.delegate = self
    pickerTest.dataSource = self
}

@IBOutlet weak var pickerTest: UIPickerView!

func numberOfComponents(in pickerView: UIPickerView) -> Int {
    return 1
}

func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
    return arrayOfNumbers.count
}

func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
    return arrayOfNumbers[row]
}

Answer 1

pickerTest.selectRow(4, inComponent: 0, animated: true)

如何在 UIPickerView 中显示需要的行？

How to show needed row in UIPickerView?

arrays

swift

uipickerview