使 Selenium 在超时错误后继续
Make Selenium continue after a timeout error
我有一个代码 returns 网站列表的标题。有时,一个网站需要花费大量的时间来加载,所以当这种情况发生时,会出现超时错误提示。我想这样做,以便在发生此类错误时,程序继续 运行 而不是完全停止。
密码是:
from pyvirtualdisplay import Display
from time import sleep
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
from selenium import webdriver
from selenium.webdriver.firefox.options import Options
display = Display(visible=0, size(800,600))
display.start()
driver = webdriver.Firefox(executable_path='/usr/local/lib/geckodriver/geckodriver')
driver.set_page_load_timeout(60)
driver.get('https://google.com')
print(driver.title)
以下代码是在 60 秒后页面未加载时发生超时的原因:
driver.set_page_load_timeout(60)
60秒后,程序停止,提示超时错误。我希望它继续下一个 url。
您可以使用 try except 来处理和传递任何错误。
from pyvirtualdisplay import Display
from time import sleep
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
from selenium import webdriver
from selenium.webdriver.firefox.options import Options
display = Display(visible=0, size(800,600))
display.start()
driver = webdriver.Firefox(executable_path='/usr/local/lib/geckodriver/geckodriver')
try:
driver.set_page_load_timeout(60)
except Exception as e:
print(e)
driver.get('https://google.com')
print(driver.title)
即使出现 page_load_timeout 错误,要遍历 List url,您可以使用以下解决方案:
代码块:
from selenium import webdriver
from selenium.common.exceptions import TimeoutException
urls = ["https://www.booking.com/hotel/in/the-taj-mahal-palace-tower.html?label=gen173nr-1FCAEoggJCAlhYSDNiBW5vcmVmaGyIAQGYATG4AQbIAQzYAQHoAQH4AQKSAgF5qAID;sid=338ad58d8e83c71e6aa78c67a2996616;dest_id=-2092174;dest_type=city;dist=0;group_adults=2;hip_dst=1;hpos=1;room1=A%2CA;sb_price_type=total;srfid=ccd41231d2f37b82d695970f081412152a59586aX1;srpvid=c71751e539ea01ce;type=total;ucfs=1&#hotelTmpl", "https://www.google.com/"]
driver = webdriver.Chrome(executable_path=r'C:\WebDrivers\chromedriver.exe')
driver.set_page_load_timeout(2)
for url in urls:
try :
driver.get(url)
print("URL successfully Accessed ... Proceeding with other tasks !!!")
# perform other operations within the url
except TimeoutException as e:
print("Page load Timeout Occured ... moving to next item !!!")
driver.quit()
控制台输出:
Page load Timeout Occured ... moving to next item !!!
Page load Timeout Occured ... moving to next item !!!
注:
set_page_load_timeout(2)
用于重现页面加载超时,仅供演示。
- urls 的 List 仅用于演示目的。
You can find a detailed discussion on page load timeout in
我有一个代码 returns 网站列表的标题。有时,一个网站需要花费大量的时间来加载,所以当这种情况发生时,会出现超时错误提示。我想这样做,以便在发生此类错误时,程序继续 运行 而不是完全停止。
密码是:
from pyvirtualdisplay import Display
from time import sleep
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
from selenium import webdriver
from selenium.webdriver.firefox.options import Options
display = Display(visible=0, size(800,600))
display.start()
driver = webdriver.Firefox(executable_path='/usr/local/lib/geckodriver/geckodriver')
driver.set_page_load_timeout(60)
driver.get('https://google.com')
print(driver.title)
以下代码是在 60 秒后页面未加载时发生超时的原因:
driver.set_page_load_timeout(60)
60秒后,程序停止,提示超时错误。我希望它继续下一个 url。
您可以使用 try except 来处理和传递任何错误。
from pyvirtualdisplay import Display
from time import sleep
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
from selenium import webdriver
from selenium.webdriver.firefox.options import Options
display = Display(visible=0, size(800,600))
display.start()
driver = webdriver.Firefox(executable_path='/usr/local/lib/geckodriver/geckodriver')
try:
driver.set_page_load_timeout(60)
except Exception as e:
print(e)
driver.get('https://google.com')
print(driver.title)
即使出现 page_load_timeout 错误,要遍历 List url,您可以使用以下解决方案:
代码块:
from selenium import webdriver from selenium.common.exceptions import TimeoutException urls = ["https://www.booking.com/hotel/in/the-taj-mahal-palace-tower.html?label=gen173nr-1FCAEoggJCAlhYSDNiBW5vcmVmaGyIAQGYATG4AQbIAQzYAQHoAQH4AQKSAgF5qAID;sid=338ad58d8e83c71e6aa78c67a2996616;dest_id=-2092174;dest_type=city;dist=0;group_adults=2;hip_dst=1;hpos=1;room1=A%2CA;sb_price_type=total;srfid=ccd41231d2f37b82d695970f081412152a59586aX1;srpvid=c71751e539ea01ce;type=total;ucfs=1&#hotelTmpl", "https://www.google.com/"] driver = webdriver.Chrome(executable_path=r'C:\WebDrivers\chromedriver.exe') driver.set_page_load_timeout(2) for url in urls: try : driver.get(url) print("URL successfully Accessed ... Proceeding with other tasks !!!") # perform other operations within the url except TimeoutException as e: print("Page load Timeout Occured ... moving to next item !!!") driver.quit()
控制台输出:
Page load Timeout Occured ... moving to next item !!! Page load Timeout Occured ... moving to next item !!!
注:
set_page_load_timeout(2)
用于重现页面加载超时,仅供演示。- urls 的 List 仅用于演示目的。
You can find a detailed discussion on page load timeout in