如何查找和复制python中子目录的内容？

Question

我有一个根文件夹，其结构如下

root
    A 
    |-30
       |-a.txt
       |-b.txt 
    |-90
       |-a.txt
       |-b.txt  
    B
    |-60
       |-a.txt
       |-b.txt  
    C
    |-200
       |-a.txt
       |-b.txt  
    |-300 
       |-a.txt
       |-b.txt

我想找到所有子文件夹 (A,B,C,D)，使得子文件夹的子文件夹（如 30,90,...）小于 60 .然后将子文件夹中名称为 a.txt 的所有文件复制到另一个目录。输出喜欢

root_filter
    A 
    |-30
       |-a.txt
    B
    |-60
       |-a.txt

我正在使用 python 但我无法获得结果

dataroot = './root'
for dir, dirs, files in os.walk(dataroot):
    print (dir,os.path.isdir(dir))

Answer 1

基本上，您只需要运行在复制文件之前检查一下您的位置。这可以通过 for 循环内的简单 if 语句中的多个子句来完成：

import shutil
import os

dataroot = './root'
target_dir = './some_other_dir'
for dir, dirs, files in os.walk(dataroot):
    # First, we want to check if we're at the right level of directory
    #   we can do this by counting the number of '/' in the name of the directory
    #   (the distance from where we started). For ./root/A/30 there should be 
    #   3 instances of the character '/'
    # Then, we want to ensure that the folder is numbered 60 or less.
    #   to do this, we isolate the name of *this* folder, cast it to an int,
    #   and then check its value
    # Finally, we check if 'a.txt' is in the directory
    if dir.count('/') == 3 and int(dir[dir.rindex('/')+1:]) <= 60 and 'a.txt' in files:
        shutil.copy(os.path.join(dir, 'a.txt'), target_dir)

当您将文件复制到 target_dir 时，您需要为文件命名，这样它们就不会相互覆盖。这取决于您的用例。

如何查找和复制python中子目录的内容？

How to find and copy the content of sub directories in python?

python

os.walk

python-3.x