读取文件 - 匹配行与列表

Question

我正在读取一个 Python 的文件，我只想提取与某些内容匹配的行。 '\ 我的问题是：如果我只为匹配传递一个字符串，我就能做到（如下面的代码）'

import sys,os
import re
import pandas as pd

path = 'file'
sports = ['Sports', 'Nature']
keyword = 'Sports'
data = pd.DataFrame([])

with open(path) as auto:
  for line in auto:
    if keyword in line:
        print(line)

我传递了一个我无法检索任何行的列表：

with open(path) as auto:
  for line in auto:
    if any(x in errors for x in line):
        print(line)

有人知道我该怎么做吗？

Answer 1

您可以使用列表理解的替代方法：

file = [line.lower() for line in open(path).readlines()]
required_line = [line for text in keyword for line in file if text.lower() in line]

根据您的方法，您遗漏了一些东西：

with open(path) as auto:
    for line in auto:
        if any(x for x in keyword for x in line):
            print(lines)

Answer 2

请查看差异，当您迭代 str 和 list、

时

>>> keyword = ['sports', 'something else']
>>> line = "line that has a word sports in it"
>>> 'sports' in line
True
>>> any(x in keyword  for x in line.split()) # iterating over list
True
>>> any(x in keyword  for x in line) # iterating over each characters in an string
False

读取文件 - 匹配行与列表

Reading file - Match line with List

python

file

sys

pandas