我怎样才能在搜索页面上获得 Youtube 视频标题
How can i get Youtube Video Title at Searching Page
我可以在 Youtube/watch?v=videolink 获取所有视频信息,但我想从 Youtube/results?search-query 获取 link 和标题页。
webCommandMetadata":{"url":"/watch?v=VIDEOID"}
我用这个正则表达式 "/\/watch\?v=(.*?)[&\"]/i"
得到了视频 url
Output:VIDEOID
但我无法在
中获得标题
title":{"accessibility":{"accessibilityData":{"label":"#VIDEOTITLE"
因为source里的标签太多了。是否可以对从标题到 :" 的所有内容进行正则表达式并输出 #VIDEOTITLE
?或其他获取方式?
从 YouTube 获取搜索结果的最佳解决方案是 YouTube Data API
(来自 YouTube 数据 API 文档)
先得到结果,再得到每个视频的标题
$searchResponse = $youtube->search->listSearch('id,snippet', array(
'q' => $_GET['q'],
'maxResults' => $_GET['maxResults'],
));
// Add each result to the appropriate list, and then display the lists of
// matching videos, channels, and playlists.
foreach ($searchResponse['items'] as $searchResult) {
switch ($searchResult['id']['kind']) {
case 'youtube#video':
$videos .= sprintf('<li>%s (%s)</li>',
$searchResult['snippet']['title'], $searchResult['id']['videoId']);
break;
case 'youtube#channel':
$channels .= sprintf('<li>%s (%s)</li>',
$searchResult['snippet']['title'], $searchResult['id']['channelId']);
break;
case 'youtube#playlist':
$playlists .= sprintf('<li>%s (%s)</li>',
$searchResult['snippet']['title'], $searchResult['id']['playlistId']);
break;
}
}
我可以在 Youtube/watch?v=videolink 获取所有视频信息,但我想从 Youtube/results?search-query 获取 link 和标题页。
webCommandMetadata":{"url":"/watch?v=VIDEOID"}
我用这个正则表达式 "/\/watch\?v=(.*?)[&\"]/i"
Output:VIDEOID
但我无法在
中获得标题title":{"accessibility":{"accessibilityData":{"label":"#VIDEOTITLE"
因为source里的标签太多了。是否可以对从标题到 :" 的所有内容进行正则表达式并输出 #VIDEOTITLE
?或其他获取方式?
从 YouTube 获取搜索结果的最佳解决方案是 YouTube Data API
(来自 YouTube 数据 API 文档)
先得到结果,再得到每个视频的标题
$searchResponse = $youtube->search->listSearch('id,snippet', array(
'q' => $_GET['q'],
'maxResults' => $_GET['maxResults'],
));
// Add each result to the appropriate list, and then display the lists of
// matching videos, channels, and playlists.
foreach ($searchResponse['items'] as $searchResult) {
switch ($searchResult['id']['kind']) {
case 'youtube#video':
$videos .= sprintf('<li>%s (%s)</li>',
$searchResult['snippet']['title'], $searchResult['id']['videoId']);
break;
case 'youtube#channel':
$channels .= sprintf('<li>%s (%s)</li>',
$searchResult['snippet']['title'], $searchResult['id']['channelId']);
break;
case 'youtube#playlist':
$playlists .= sprintf('<li>%s (%s)</li>',
$searchResult['snippet']['title'], $searchResult['id']['playlistId']);
break;
}
}