链表段错误

Question

我遇到了分段错误，但我不知道问题出在哪里。

#include "stdio.h"
#include "stdlib.h"

struct node {
    int data;
    struct node *next;
    };
    struct node *head = NULL;
    struct node * curr;
    struct node * newNode;

void createList(){

    int data,n , i ;
    scanf("%d",&n);
    for (i = 0 ; i < n ;i++){
        scanf("%d",&data);
        curr = head;
        newNode = (struct node*)malloc(sizeof(struct node));
        newNode->data=data;
        newNode->next=NULL;
        if ( curr == NULL){
            head = newNode;
        }else
            while (curr->next != NULL){
                curr = curr->next;
            }
            curr->next = newNode;
    }

}

int main(int argc, char const *argv[])
{

    createList();
    return 0;
}

你能知道在哪里吗？第一次迭代很好，但是i = 1时出现错误。

Answer 1

对齐不足以在 C 中生成块代码 ;-)

需要牙套。没有它，语句 curr->next = newNode; 位于 else 块之外，这不是您想要的。

  if ( curr == NULL){
                head = newNode;
   }
   else {
                while (curr->next != NULL){
                    curr = curr->next;
                }
                curr->next = newNode;
   }

链表段错误

Linked List Seg Faults

c

linked-list