使用 gmail smtp 发送邮件、换行符和发件人 header

Mail Sending, Line break & and From header using gmail smtp

我用 PHPMailer 发送电子邮件,我的代码是:

$mail = new PHPMailer(true);
$mail->Mailer       = "smtp";
$mail->IsSMTP();  // telling the class to use SMTP
$mail->SMTPDebug    = 0; 
$mail->SMTPSecure = 'tls';
$mail->Host     = "smtp.gmail.com"; // SMTP server
$mail->Username   = "nati323@gmail.com";
$mail->Password   = "****";
$mail->addCustomHeader('Content-Type: text/plain; charset="utf-8"');
$mail->SMTPAuth   = true;       
$mail->Port       = 587;
$mail->From     = $from;
$mail->AddAddress($to);
$mail->Subject  = $subject;
$mail->Body     = $msg;
return $mail->Send();

$msg 变量是一个函数参数,我这样使用它:

function sendMail ($to, $subject, $msg, $from, $add = null)

我是这样使用它的:

sendMail($_POST['mail'], $text['EMAIL_RECOVER_MSG_SUBJECT'], $text['EMAIL_RECOVER_MSG'], $from)

变量包含:

$text['EMAIL_RECOVER_MSG_SUBJECT'] = 'Password Recover: From dmworld24.com';
$text['EMAIL_RECOVER_MSG'] = 'You Forget Your Password To Recover it Please Go Into The Next Link:\r\n http://dmworld24.com/login.php?act=rec&token={TOKEN}&mail={MAIL} \r\n If You Didnt Ask For Password Recovering Just Ignore This Message';
$from = 'System@dmworld24.com';

现在我尝试在消息中添加换行符,例如:

You Forget Your Password To Recover it Please Go Into The Next Link:\r\n http://dmworld24.com/login.php?act=rec&token=7054343021*****353214&mail=nati323@gmail.com \r\n If You Didnt Ask For Password Recovering Just Ignore This Message

和我在邮件中收到的一样,\r\n显示为字符并且没​​有换行符,我做错了什么?

我遇到的另一个问题是表单方法 dosent 工作,我发送电子邮件尝试 nati323@gmail.com,然后我使用 nati323@gmail.com 帐户连接到 smtp 服务器,然后我总是从我自己那里得到消息,我定义的表格显示....

调用PHP函数nl2br()将换行符转换为HTML换行符。然后,将 PHPMailer 设置为使用 $mail->IsHTML(TRUE);

作为 html 发送电子邮件

您在邮件中使用了单引号。这将按字面意思获取其中包含的所有内容,这就是为什么您会得到文字字符串 \r\n。

将单引号替换为双引号以正确输出新行。

$text['EMAIL_RECOVER_MSG'] = "You Forget Your Password To Recover it Please Go Into The Next Link:\r\n http://dmworld24.com/login.php?act=rec&token={TOKEN}&mail={MAIL} \r\n If You Didnt Ask For Password Recovering Just Ignore This Message";`