Flutter - 通知 Column 内的兄弟小部件
Flutter - notify sibling widgets inside Column
我正在尝试创建一个功能,当我点击 Expanded
小部件内的 FlatButton
时,它的 flex
变为 2 和其他兄弟姐妹 FlatButton
灵活更改为 1。
import 'package:flutter/material.dart';
void main() {
runApp(MyApp());
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return Directionality(
textDirection: TextDirection.ltr,
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
new ButtonWidget(text: "Hello",selectedColor: Colors.yellow),
new ButtonWidget(text: "This is", selectedColor: Colors.red),
new ButtonWidget(text: "Button", selectedColor: Colors.blue),
],
),
);
}
}
class ButtonWidget extends StatefulWidget {
String text;
MaterialColor selectedColor;
ButtonWidget({this.text, this.selectedColor});
createState() =>
ButtonState(text: this.text, selectedColor: this.selectedColor);
}
class ButtonState extends State<ButtonWidget> {
String text;
MaterialColor selectedColor;
int _flexValue = 1;
ButtonState({this.text, this.selectedColor});
@override
Widget build(BuildContext context) {
return Expanded(
flex: _flexValue,
child: FlatButton(
color: selectedColor,
child: Text(
text,
),
onPressed: () {
setState(() {
_flexValue = 2;
});
},
),
);
}
}
我试图找到一种方法,也许可以在数组或其他东西中跟踪所有这些。我搜索并发现 InheritedWidget
方法适用于继承的小部件,而不是兄弟。
我相信有一种干净的方法可以做到这一点。但是就是拿不到。
这里有另一种方法,将主小部件更改为 Stateful
,将按钮更改为 Stateless
。
class MyApp2 extends StatefulWidget {
@override
_MyApp2State createState() => _MyApp2State();
}
class _MyApp2State extends State<MyApp2> {
int selectedIndex = -1;
onIndexChanged(int index){
setState(() {
selectedIndex = index;
});
}
@override
Widget build(BuildContext context) {
return Directionality(
textDirection: TextDirection.ltr,
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
new ButtonWidget(
index: 1,
text: "Hello",
selectedColor: Colors.yellow,
selectedIndex: selectedIndex,
onChanged: onIndexChanged
),
new ButtonWidget(
index: 2,
text: "This is",
selectedColor: Colors.red,
selectedIndex: selectedIndex,
onChanged: onIndexChanged),
new ButtonWidget(
index: 3,
text: "Button",
selectedColor: Colors.blue,
selectedIndex: selectedIndex,
onChanged: onIndexChanged),
],
),
);
}
}
class ButtonWidget extends StatelessWidget {
final String text;
final MaterialColor selectedColor;
final int index;
final ValueChanged<int> onChanged;
final int selectedIndex;
ButtonWidget(
{this.text,
this.selectedColor,
this.index,
this.onChanged,
this.selectedIndex});
@override
Widget build(BuildContext context) {
return Expanded(
flex: selectedIndex != null && selectedIndex == index ? 2 : 1,
child: FlatButton(
color: selectedColor,
child: Text(
text,
),
onPressed: () => onChanged(index),
),
);
}
}
不要试图在按钮本身中保持是否被选中的状态。如您所见,很难使 3 个按钮的状态保持同步。在小部件树上找到一个可以维护该状态一次的位置。在这种情况下,它在您的应用程序中。使应用程序有状态,以便它可以记住状态,然后您的按钮就不需要记住它。可以在构造函数中告知它们是被选中(大)还是未被选中(小)。
那么,按钮如何告诉父级它现在已被选中?有多种策略,但它们都涉及:
- 调用传递下来的方法
- 在 InheritedWidget 上调用方法
- 通过流发送消息
- 等等
试试这个:
import 'package:flutter/material.dart';
void main() {
runApp(MyApp());
}
class MyApp extends StatefulWidget {
@override
State createState() => MyAppState();
}
class MyAppState extends State<MyApp> {
int selected = 0;
@override
Widget build(BuildContext context) {
return Directionality(
textDirection: TextDirection.ltr,
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
ButtonWidget(0, flexValue(0), 'Hello', Colors.yellow, onClick),
ButtonWidget(1, flexValue(1), 'This is', Colors.red, onClick),
ButtonWidget(2, flexValue(2), 'Button', Colors.blue, onClick),
],
),
);
}
void onClick(int i) {
setState(() {
selected = i;
});
}
int flexValue(int index) => (index == selected) ? 2 : 1;
}
class ButtonWidget extends StatelessWidget {
ButtonWidget(this.index, this._flexValue, this.text, this.selectedColor,
this.notifyClick);
final Function notifyClick;
final int index;
final int _flexValue;
final String text;
final MaterialColor selectedColor;
@override
Widget build(BuildContext context) {
return Expanded(
flex: _flexValue,
child: FlatButton(
color: selectedColor,
child: Text(
text,
),
onPressed: () {
notifyClick(index);
},
),
);
}
}
我正在尝试创建一个功能,当我点击 Expanded
小部件内的 FlatButton
时,它的 flex
变为 2 和其他兄弟姐妹 FlatButton
灵活更改为 1。
import 'package:flutter/material.dart';
void main() {
runApp(MyApp());
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return Directionality(
textDirection: TextDirection.ltr,
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
new ButtonWidget(text: "Hello",selectedColor: Colors.yellow),
new ButtonWidget(text: "This is", selectedColor: Colors.red),
new ButtonWidget(text: "Button", selectedColor: Colors.blue),
],
),
);
}
}
class ButtonWidget extends StatefulWidget {
String text;
MaterialColor selectedColor;
ButtonWidget({this.text, this.selectedColor});
createState() =>
ButtonState(text: this.text, selectedColor: this.selectedColor);
}
class ButtonState extends State<ButtonWidget> {
String text;
MaterialColor selectedColor;
int _flexValue = 1;
ButtonState({this.text, this.selectedColor});
@override
Widget build(BuildContext context) {
return Expanded(
flex: _flexValue,
child: FlatButton(
color: selectedColor,
child: Text(
text,
),
onPressed: () {
setState(() {
_flexValue = 2;
});
},
),
);
}
}
我试图找到一种方法,也许可以在数组或其他东西中跟踪所有这些。我搜索并发现 InheritedWidget
方法适用于继承的小部件,而不是兄弟。
我相信有一种干净的方法可以做到这一点。但是就是拿不到。
这里有另一种方法,将主小部件更改为 Stateful
,将按钮更改为 Stateless
。
class MyApp2 extends StatefulWidget {
@override
_MyApp2State createState() => _MyApp2State();
}
class _MyApp2State extends State<MyApp2> {
int selectedIndex = -1;
onIndexChanged(int index){
setState(() {
selectedIndex = index;
});
}
@override
Widget build(BuildContext context) {
return Directionality(
textDirection: TextDirection.ltr,
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
new ButtonWidget(
index: 1,
text: "Hello",
selectedColor: Colors.yellow,
selectedIndex: selectedIndex,
onChanged: onIndexChanged
),
new ButtonWidget(
index: 2,
text: "This is",
selectedColor: Colors.red,
selectedIndex: selectedIndex,
onChanged: onIndexChanged),
new ButtonWidget(
index: 3,
text: "Button",
selectedColor: Colors.blue,
selectedIndex: selectedIndex,
onChanged: onIndexChanged),
],
),
);
}
}
class ButtonWidget extends StatelessWidget {
final String text;
final MaterialColor selectedColor;
final int index;
final ValueChanged<int> onChanged;
final int selectedIndex;
ButtonWidget(
{this.text,
this.selectedColor,
this.index,
this.onChanged,
this.selectedIndex});
@override
Widget build(BuildContext context) {
return Expanded(
flex: selectedIndex != null && selectedIndex == index ? 2 : 1,
child: FlatButton(
color: selectedColor,
child: Text(
text,
),
onPressed: () => onChanged(index),
),
);
}
}
不要试图在按钮本身中保持是否被选中的状态。如您所见,很难使 3 个按钮的状态保持同步。在小部件树上找到一个可以维护该状态一次的位置。在这种情况下,它在您的应用程序中。使应用程序有状态,以便它可以记住状态,然后您的按钮就不需要记住它。可以在构造函数中告知它们是被选中(大)还是未被选中(小)。
那么,按钮如何告诉父级它现在已被选中?有多种策略,但它们都涉及:
- 调用传递下来的方法
- 在 InheritedWidget 上调用方法
- 通过流发送消息
- 等等
试试这个:
import 'package:flutter/material.dart';
void main() {
runApp(MyApp());
}
class MyApp extends StatefulWidget {
@override
State createState() => MyAppState();
}
class MyAppState extends State<MyApp> {
int selected = 0;
@override
Widget build(BuildContext context) {
return Directionality(
textDirection: TextDirection.ltr,
child: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
ButtonWidget(0, flexValue(0), 'Hello', Colors.yellow, onClick),
ButtonWidget(1, flexValue(1), 'This is', Colors.red, onClick),
ButtonWidget(2, flexValue(2), 'Button', Colors.blue, onClick),
],
),
);
}
void onClick(int i) {
setState(() {
selected = i;
});
}
int flexValue(int index) => (index == selected) ? 2 : 1;
}
class ButtonWidget extends StatelessWidget {
ButtonWidget(this.index, this._flexValue, this.text, this.selectedColor,
this.notifyClick);
final Function notifyClick;
final int index;
final int _flexValue;
final String text;
final MaterialColor selectedColor;
@override
Widget build(BuildContext context) {
return Expanded(
flex: _flexValue,
child: FlatButton(
color: selectedColor,
child: Text(
text,
),
onPressed: () {
notifyClick(index);
},
),
);
}
}