如何从 Django 管理员上传多个文件?
How to upload multiple files from the Django admin?
我想在 Django 管理中上传多个文件,而不必放置多个 FileField 字段。用户可以通过简单的方式管理文件;删除或更改每个上传的文件,但同时上传多个文件。
我认为可行的解决方案是使用多个文件字段,但问题是,我不知道用户将上传多少文件
def case_upload_location(instance, filename):
case_name = instance.name.lower().replace(" ", "-")
file_name = filename.lower().replace(" ", "-")
return "casos/{}/{}".format(case_name, file_name)
class Case(models.Model):
name = models.CharField(max_length=250)
observations = models.TextField(null = True, blank = True)
number_folder = models.CharField('Folder', max_length=250)
file1 = models.FileField('file 1', upload_to=case_upload_location, null = True, blank = True)
file2 = models.FileField('file 2', upload_to=case_upload_location, null = True, blank = True)
file3 = models.FileField('file 3', upload_to=case_upload_location, null = True, blank = True)
file4 = models.FileField('file 4', upload_to=case_upload_location, null = True, blank = True)
最终目标
要上传多个文件(用户需要一个一个删除或更改,但一次上传)。
看起来您需要从 "Case File" 模型到您定义的 "Case" 模型的一对多外键关系。
models.py
from django.db import models
def case_upload_location(instance, filename):
case_name = instance.name.lower().replace(" ", "-")
file_name = filename.lower().replace(" ", "-")
return "casos/{}/{}".format(case_name, file_name)
class Case(models.Model):
# datos del caso
name = models.CharField('Nombre', max_length=250)
observations = models.TextField('Observaciones', null = True, blank = True)
number_folder = models.CharField('Numero de Carpeta', max_length=250)
class CaseFile(models.Model):
case = models.ForeignKey(Case, on_delete=models.CASCADE) # When a Case is deleted, upload models are also deleted
file = models.FileField(upload_to=case_upload_location, null = True, blank = True)
然后您可以添加 StackedInline 管理表单以将案例文件直接添加到给定案例。
admin.py
from django.contrib import admin
from .models import Case, CaseFile
class CaseFileAdmin(admin.StackedInline):
model = CaseFile
@admin.register(Case)
class CaseAdmin(admin.ModelAdmin):
inlines = [CaseFileAdmin]
@admin.register(CaseFile)
class CaseFileAdmin(admin.ModelAdmin):
pass
我想在 Django 管理中上传多个文件,而不必放置多个 FileField 字段。用户可以通过简单的方式管理文件;删除或更改每个上传的文件,但同时上传多个文件。
我认为可行的解决方案是使用多个文件字段,但问题是,我不知道用户将上传多少文件
def case_upload_location(instance, filename):
case_name = instance.name.lower().replace(" ", "-")
file_name = filename.lower().replace(" ", "-")
return "casos/{}/{}".format(case_name, file_name)
class Case(models.Model):
name = models.CharField(max_length=250)
observations = models.TextField(null = True, blank = True)
number_folder = models.CharField('Folder', max_length=250)
file1 = models.FileField('file 1', upload_to=case_upload_location, null = True, blank = True)
file2 = models.FileField('file 2', upload_to=case_upload_location, null = True, blank = True)
file3 = models.FileField('file 3', upload_to=case_upload_location, null = True, blank = True)
file4 = models.FileField('file 4', upload_to=case_upload_location, null = True, blank = True)
最终目标
要上传多个文件(用户需要一个一个删除或更改,但一次上传)。
看起来您需要从 "Case File" 模型到您定义的 "Case" 模型的一对多外键关系。
models.py
from django.db import models
def case_upload_location(instance, filename):
case_name = instance.name.lower().replace(" ", "-")
file_name = filename.lower().replace(" ", "-")
return "casos/{}/{}".format(case_name, file_name)
class Case(models.Model):
# datos del caso
name = models.CharField('Nombre', max_length=250)
observations = models.TextField('Observaciones', null = True, blank = True)
number_folder = models.CharField('Numero de Carpeta', max_length=250)
class CaseFile(models.Model):
case = models.ForeignKey(Case, on_delete=models.CASCADE) # When a Case is deleted, upload models are also deleted
file = models.FileField(upload_to=case_upload_location, null = True, blank = True)
然后您可以添加 StackedInline 管理表单以将案例文件直接添加到给定案例。
admin.py
from django.contrib import admin
from .models import Case, CaseFile
class CaseFileAdmin(admin.StackedInline):
model = CaseFile
@admin.register(Case)
class CaseAdmin(admin.ModelAdmin):
inlines = [CaseFileAdmin]
@admin.register(CaseFile)
class CaseFileAdmin(admin.ModelAdmin):
pass