Laravel 5.5 只加载当前登录用户的数据

Question

嗨，我是 laravel 的新手，但我想加载当前登录用户的所有预订。

我试过这样做

   //check if user is logged in
     if ($user = Auth::user()) {  
       //get only the bookings for the currently logged in user
        $allProducts =Booking::where('client', Auth::user()->name)->where('name', $name)->first();
        //store the bookings in a products variable
        $products = json_decode(json_encode($allProducts));
      //Loop through the products:
        foreach ($products as $key => $val) {
            //get the name of the service by matching it's id in the service model to the service column in the products
            $service_name = Service::where(['id' => $val->service])->first();
      //get the charge amount of the service by matching it's id in the Charge model to the charge column in the products
            $service_fee = Charge::where(['id' => $val->charge])->first();
          //get the status of the service by matching it's id in the status model to the status column in the products
            $service_status = Status::where(['id' => $val->status])->first();
            $products[$key]->service_name = $service_name->name;
            $products[$key]->service_fee = $service_fee->total;
            $products[$key]->service_status = $service_status->name;
        }
        return view('client.booking.view_bookings')->with(compact('products'));
    }
    return view('/login');
}

但这给我一个错误：未定义的变量：行上的名称

       $allProducts =Booking::where('client', Auth::user()->name)->where('name', $name)->first();

我做错了什么？以及如何解决它以仅显示所需的数据

Answer 1

我试图理解你在做什么，但没有成功，但从你在评论中的解释，我想我知道你想做什么。

既然你说这段代码很适合你，除了它会为你提供数据库中所有数据的结果，而不考虑登录用户

    $allProducts = Booking::get();

这是因为创建了一个查询，该查询选择了数据库中的所有数据。

您需要在语句中添加一个 where 子句。要做到这一点，只需将其添加到上面的代码行

    where('client', Auth::user()->name)

它将 return 仅包含与当前登录用户名称相同的客户端列的数据。

因此整行代码变为；

    $allProducts = Booking::get()->where('client', Auth::user()->name);

或者您可以使用过滤器

Laravel 5.5 只加载当前登录用户的数据

Laravel 5.5 load only the data for the currently logged in user

laravel-5.5