如何在 sql 服务器 2014 中将经度和纬度存储为地理信息?

How to store longitude & latitude as a geography in sql server 2014?

我在经度和纬度坐标中有位置。我的目标是最终能够 select myTable 中距离小于 2km 的所有行。

  1. 如何使用经度和纬度在地理列中存储位置?(因为它应该只是一个地理点而不是两个,对吗?不是一个用于经度,一个用于纬度?)

  2. 现在我已经有了地理点,我怎样才能 select 特定距离内的所有行(在我的例子中是 2 公里)?

How can i use the longitute and latitute to store location within a geography column?(because it's supposed to be only one geographic point not two right? not one for longitute and one for latitute?)

您可以使用 geography::STPointFromText / geography::Point 以地理数据类型存储经度和纬度。

SELECT geography::STPointFromText('POINT(' + CAST([Longitude] AS VARCHAR(20)) + ' ' + CAST([Latitude] AS VARCHAR(20)) + ')', 4326)

SELECT geography::Point(Latitude, Longitude , 4326)

引用Link:

Now that I've got the geography points, how can i select all the rows within a specific distance(in my case 2km)?

你可以这样使用STDistance

DECLARE @g geography;
DECLARE @h geography;
SET @g = geography::STGeomFromText('POINT(-122.35900 47.65129)', 4326);
SET @h = geography::STGeomFromText('POINT(-122.34720 47.65100)', 4326);
SELECT @g.STDistance(@h);

引用Link:

Distance between two points using Geography datatype in sqlserver 2008?

插入查询

DECLARE @GeoTable TABLE 
(
    id int identity(1,1),
    location geography
)
--Using geography::STGeomFromText
INSERT INTO @GeoTable 
SELECT geography::STGeomFromText('POINT(-122.35900 47.65129)', 4326)

--Using geography::Point
INSERT INTO @GeoTable 
SELECT geography::Point(47.65100,-122.34720, 4326);

获取距离查询

DECLARE @DistanceFromPoint geography
SET @DistanceFromPoint =  geography::STGeomFromText('POINT(-122.34150 47.65234)', 4326);

SELECT id,location.Lat Lat,location.Long Long,location.STDistance(@DistanceFromPoint) Distance
FROM @GeoTable;

以上回答@ughai的补充

添加一列

 ALTER TABLE [dbo].[Landmark]
 ADD [GeoLocation] GEOGRAPHY
 GO

将经度和纬度转换为地理

UPDATE [dbo].[Landmark]
SET [GeoLocation] = geography::STPointFromText('POINT(' + CAST([Longitude] 
AS VARCHAR(20)) + ' ' + 
                CAST([Latitude] AS VARCHAR(20)) + ')', 4326)
GO

寻找半径为 2 公里的地点

DECLARE @Origin GEOGRAPHY,
    -- distance defined in meters
    @Distance INTEGER = 2000;        


 SET @Origin = GEOGRAPHY::STGeomFromText('POINT(17.482477 78.546871)', 4326);

 -- return all rows from events in 2km radius
SELECT *,GeoLocation.STDistance(@Origin) Distance FROM dbo.Locations WHERE @Origin.STDistance(GeoLocation) <= @Distance;

它让我找到了距离内的地方

您可以将纬度和经度转换为点并将其保存在 table。

声明@geo地理, @Lat varchar(10), @long varchar(10)

SET @Lat = '34.738925' SET @Long = '-92.39764'

SET @geo= geography::Point(@LAT, @LONG, 4326)

在存储过程和选择中使用 GeoPoints 时,总是计算 GeoPoint 变得很累,所以我发现创建一个计算列从 [=16] 生成 GeoPoint 很方便=] FLOAT 字段,当行被选中时。

[GeoPoint]  AS ([geography]::Point([Latitude],[Longitude],(4326))) PERSISTED,