在 Swift 中的字符串中删除 link 的正则表达式

Question

我有一堆从服务中收到的字符串，需要更改文本以提取和删除 3 种类型的 link，如下所述

anchor - [anchor:info]Account Details[/anchor]
action -  [action:contact]Contact info[/anchor]
link-to - [link-to:register]Create An Account[/link-to]

来自服务的全长文本示例：

"There's a problem with your [anchor:info]Account Details[/anchor]."
"There's a problem with your [anchor:rewards]Sign Up For Rewards[/anchor]."
"We didn't recognize this account. Please re-enter your email or [link-to:register]Create An Account[/link-to]."

预期结果应该是：

"There's a problem with your Account Details."
"There's a problem with your Sign Up For Rewards."
"We didn't recognize this account. Please re-enter your email or Create An Account."

我想我会使用 replacingOccurrences 函数来实现这一点。但是我还没有破解我需要的格式的正则表达式。

let aString = "There's a problem with your [anchor:info]Account Details[/anchor]."
let newString = aString.replacingOccurrences(of: "regex here", with: " ", options: .regularExpression, range: nil)

我可以使用 3 个单独的正则表达式来匹配这 3 个案例，或者使用一个可以处理以下内容的正则表达式：

[any_link_type:any_identifier]Any Text[/any_link_type]

一些正则表达式专家可以帮我解决这个问题吗？

Answer 1

知道了 :) 这个正则表达式可以满足我的要求：\[.*?\]

let linkString = "We didn't recognize this account. Please re-enter your email or [link-to:register]Create An Account[/link-to]."

let newLinkString = linkString.replacingOccurrences(of: "\[.*?\]", with: "", options: .regularExpression, range: nil)

Answer 2

试试这个模式^([^[]+)\[([^:\]]+)[^\]]*\]([^[]+)\[\/\]

并替换为</code>。</p> <p>解释：</p> <p><code>^ - 字符串的开头

([^[]+) - 匹配 [ 以外的一个或多个字符并存储在捕获组

\[ - 按字面意思匹配 [

([^:\]]+) - 匹配 : 或 ] 以外的一个或多个字符并存储在捕获组

[^\]]* - 匹配 ]

以外的零个或多个字符

\] - 按字面意思匹配 ]

([^[]+) - 匹配 [ 以外的一个或多个字符并存储在捕获组

\[\/ - 按字面意思匹配 [/

</code> - 匹配与第二个捕获组中匹配的相同文本（因此它匹配结束标记，如 <code>anchor）

\] - 按字面意思匹配 ]

Demo

Answer 3

使用以下代码获得预期的输出。

Swift 4:-

let aString = "There's a problem with your [anchor:info]Account Details[/anchor]."
let newString = aString.replacingOccurrences(of: "\[.*?\]", with: "", options: .regularExpression, range: nil)
print(newString) //There's a problem with your Account Details.

Swift 5:-

let aString = "There's a problem with your [anchor:info]Account Details[/anchor]."
let newString = aString.replacingOccurrences(of: #"\[.*?\]"#, with: " ", options: .regularExpression, range: nil)
print(newString) //There's a problem with your Account Details.

在 Swift 中的字符串中删除 link 的正则表达式

Regular expression to remove link in String in Swift

regex

macos

ios

nsregularexpression

swift