为什么在使用 serde-xml-rs 反序列化 XML 时出现错误 "missing field"，即使该元素存在？

Question

我有以下 XML 文件

<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<project name="project-name">
    <libraries>
        <library groupId="org.example" artifactId="&lt;name&gt;" version="0.1"/>
        <library groupId="com.example" artifactId="&quot;cool-lib&amp;" version="999"/>
    </libraries>
</project>

我想使用 serde-xml-rs 将它反序列化到这个结构层次结构中：

#[derive(Deserialize, Debug)]
struct Project {
    name: String,
    libraries: Libraries
}

#[derive(Deserialize, Debug)]
struct Libraries {
    libraries: Vec<Library>,
}

#[derive(Deserialize, Debug)]
struct Library {
    groupId: String,
    artifactId: String,
    version: String,
}

我正在尝试使用以下代码从文件中读取。

let file = File::open("data/sample_1.xml").unwrap();
let project: Project = from_reader(file).unwrap();

我收到此错误消息 "missing field libraries":

thread 'main' panicked at 'called `Result::unwrap()` on an `Err` value: Error(Custom("missing field `libraries`"), State { next_error: None, backtrace: None })', src/libcore/result.rs:997:5
note: Run with `RUST_BACKTRACE=1` environment variable to display a backtrace.

Answer 1

按照 GitHub repository 中的示例，您缺少注释：

#[derive(Deserialize, Debug)]
struct Libraries {
    #[serde(rename = "library")]
    libraries: Vec<Library>
}

这样我就得到了 XML 文件的正确反序列化表示

project = Project {
    name: "project-name",
    libraries: Libraries {
        libraries: [
            Library {
                groupId: "org.example",
                artifactId: "<name>",
                version: "0.1"
            },
            Library {
                groupId: "com.example",
                artifactId: "\"cool-lib&",
                version: "999"
            }
        ]
    }
}

为什么在使用 serde-xml-rs 反序列化 XML 时出现错误 "missing field"，即使该元素存在？

Why do I get the error "missing field" when deserializing XML with serde-xml-rs, even though the element is present?

xml

rust

serde