Java

Question

我有 yaml 格式的 openapi 3.0 规范和从中生成代码的应用程序。除了 swagger ui 的生成，一切正常。我使用 spring-fox 作为它的生成器，但它似乎从控制器生成了 swagger ui 2.0 版本，这些控制器是根据 openapi 规范生成的。

如何直接从我的 3.0 规范而不是从 3.0 openapi 规范生成的控制器生成 swagger ui？

Answer 1

嗯，我已经解决了问题（虽然解决起来很麻烦）。

首先我添加了 swagger ui webjar -

        <plugin>
            <!-- Download Swagger UI webjar. -->
            <artifactId>maven-dependency-plugin</artifactId>
            <version>${maven-dependency-plugin.version}</version>
            <executions>
                <execution>
                    <phase>prepare-package</phase>
                    <goals>
                        <goal>unpack</goal>
                    </goals>
                    <configuration>
                        <artifactItems>
                            <artifactItem>
                                <groupId>org.webjars</groupId>
                                <artifactId>swagger-ui</artifactId>
                                <version>${swagger-ui.version}</version>
                            </artifactItem>
                        </artifactItems>
                        <outputDirectory>${project.build.directory}/classes</outputDirectory>
                    </configuration>
                </execution>
            </executions>
        </plugin>

然后我将我的 yaml 规范转换为 json 格式并将其复制到 swagger-ui webjar 目录：

            <plugin>
                <groupId>org.openapitools</groupId>
                <artifactId>openapi-generator-maven-plugin</artifactId>
                <version>4.0.0-beta3</version>
                <executions>                    
                    <execution>
                        <id>generate-spec</id>
                        <goals>
                            <goal>generate</goal>
                        </goals>
                        <configuration>
                            <inputSpec>${openapi-spec-file-location}</inputSpec>
                            <validateSpec>true</validateSpec>
                            <generatorName>openapi</generatorName>
                            <output>${project.build.directory}/classes/META-INF/resources/webjars/swagger-ui/${swagger-ui.version}</output>
                        </configuration>
                    </execution>
                </executions>
            </plugin>

接下来我们需要在swagger-ui中设置规范路径。根据 swagger-ui API 我们可以传递 spec JSON 变量而不是 url。因此，为了初始化这个 spec 变量并编辑 swagger ui 渲染，我在 maven 中使用了 replacer 插件：

            <plugin>
                <!-- Replace the OpenAPI specification example URL with the local one. -->
                <groupId>com.google.code.maven-replacer-plugin</groupId>
                <artifactId>replacer</artifactId>
                <version>1.5.3</version>
                <executions>
                    <execution>
                        <phase>prepare-package</phase>
                        <goals>
                            <goal>replace</goal>
                        </goals>
                    </execution>
                </executions>
                <configuration>
                    <includes>
                        <!-- Static index html with swagger UI rendering and OAS in JSON format. -->
                        <include>${project.build.directory}/classes/META-INF/resources/webjars/swagger-ui/${swagger-ui.version}/index.html</include>
                        <include>${project.build.directory}/classes/META-INF/resources/webjars/swagger-ui/${swagger-ui.version}/openapi.json</include>
                    </includes>
                    <regexFlags>
                        <regexFlag>CASE_INSENSITIVE</regexFlag>
                        <regexFlag>MULTILINE</regexFlag>
                    </regexFlags>
                    <replacements>
                        <!-- This replacement imports spec json variable into static html page. -->
                        <replacement>
                            <token>&lt;script&gt;</token>
                            <value>&lt;script src="./openapi.json"&gt; &lt;/script&gt;&lt;script&gt;</value>
                        </replacement>
                        <!-- This part replaces url input variable with spec variable. -->
                        <replacement>
                            <token>url:\s"https:\/\/petstore\.swagger\.io\/v2\/swagger\.json"</token>
                            <value>spec: spec</value>
                        </replacement>
                        <replacement>
                        <!-- This replacement initializes spec variable, that will be passed to swagger ui index.html. -->
                            <token>^\{</token>
                            <value>spec = {</value>
                        </replacement>
                    </replacements>
                </configuration>
            </plugin>

所以在 build 之后的这一步，我们用 swagger ui 获得了静态资源。最后要做的是用 Spring.

来服务它

@Configuration
@EnableWebMvc
public class SwaggerConfiguration implements WebMvcConfigurer {

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/**")
                .addResourceLocations("classpath:/META-INF/resources/webjars/swagger-ui/3.22.0/");
    }

    //this method was introduced just for convenient swagger ui access. Without it swagger ui can be accessed with /index.html GET call   
    @Override
    public void addViewControllers(ViewControllerRegistry registry) {
        registry.addViewController("/swagger-ui.html").setViewName("forward:/index.html");
    }
}

就是这样。如果您评论此答案并指出如何简化此过程，那就太好了。

Java - 如何直接从 openapi 3.0 规范生成 Swagger UI

Java - how to generate Swagger UI directly from openapi 3.0 specification

swagger

springfox

openapi