SQL COUNT(DISTINCT(field1)) GROUP BY MAX(filed2)

Question

我有一个table喜欢

name  num_try

John     2
John     1
Mike     3
Mike     2
Linda    2

我想知道按 MAX(num_try).

对不同名称进行分组

想要的结果应该是这样的

MAX(num_try)  COUNT(DISTINCT(names))
     2            2
     3            1

你能帮我解决这个问题吗？

Answer 1

select max_num_try, count(*) from 
(
   select name, max(num_try) as max_num_try
   from table1
   group by name
) a
group by max_num_try
order by max_num_try desc

SQL COUNT(DISTINCT(field1)) GROUP BY MAX(filed2)

SQL COUNT(DISTINCT(field1)) GROUP BY MAX(filed2)

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