按下一个键激活键盘记录器并让它 运行 持续一段时间
activate keylogger with the press of a key and have it running for a set amount of time
我想要一个键盘记录器,它通过按下一个键(任何键)激活,然后将在设定时间(例如 10 秒)内按下的所有键保存在一个列表中,然后打印出来。
我试过这个:
from pynput import keyboard
from time import sleep
def on_press(key):
global recording, keys_pressed
if not recording:
recording = True
sleep(10)
print(" ".join(keys_pressed))
recording = False
listener = keyboard.Listener(
on_press=on_press)
listener.start()
def on_release(key):
global recording
if recording:
print("key pressed")
global keys_pressed
Key = str(key)
if Key.startswith("Key."):
keys_pressed.append(Key[4:].strip("'"))
else:
keys_pressed.append(str(key).strip("'"))
listener2 = keyboard.Listener(
on_release=on_release)
listener2.start()
keys_pressed = []
recording = False
while True:
pass
它有点管用,但它会多次打印我显然不想要的列表。程序运行起来也特别慢
如果您知道任何解决方案,请告诉我。
它多次打印我显然不想要的列表
你明确要求它在每次按下按钮时打印列表
print(" ".join(keys_pressed))
此外,我无法理解您为什么要尝试实现 2 个侦听器???
我会做更多类似的事情,尽管我确信还有更漂亮的解决方案!
from pynput import keyboard
from time import time
my_log = []
started = False
start_time = time() # just here to initialize, won't be used until started = True
def on_press(key):
global started
global start_time
if started is False:
started = True
start_time = time()
print("starting timer")
try:
character = '{0}'.format(key.char)
except AttributeError:
character = '{0}'.format(key)
my_log.append(character)
def listen():
global started
print('keyboard listener is initialized')
with keyboard.Listener(on_press=on_press):
while True:
if started:
now = time()
if now - start_time > 10:
break
return # end our listener
listen()
print("done listening")
print(my_log)
示例输出看起来像(有点乱,因为打印与键入的内容相结合):
keyboard listener is initialized
astarting timer
bcdefghijklmnopqrstuvwxyzdone listening
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
我想要一个键盘记录器,它通过按下一个键(任何键)激活,然后将在设定时间(例如 10 秒)内按下的所有键保存在一个列表中,然后打印出来。 我试过这个:
from pynput import keyboard
from time import sleep
def on_press(key):
global recording, keys_pressed
if not recording:
recording = True
sleep(10)
print(" ".join(keys_pressed))
recording = False
listener = keyboard.Listener(
on_press=on_press)
listener.start()
def on_release(key):
global recording
if recording:
print("key pressed")
global keys_pressed
Key = str(key)
if Key.startswith("Key."):
keys_pressed.append(Key[4:].strip("'"))
else:
keys_pressed.append(str(key).strip("'"))
listener2 = keyboard.Listener(
on_release=on_release)
listener2.start()
keys_pressed = []
recording = False
while True:
pass
它有点管用,但它会多次打印我显然不想要的列表。程序运行起来也特别慢
如果您知道任何解决方案,请告诉我。
它多次打印我显然不想要的列表
你明确要求它在每次按下按钮时打印列表
print(" ".join(keys_pressed))
此外,我无法理解您为什么要尝试实现 2 个侦听器???
我会做更多类似的事情,尽管我确信还有更漂亮的解决方案!
from pynput import keyboard
from time import time
my_log = []
started = False
start_time = time() # just here to initialize, won't be used until started = True
def on_press(key):
global started
global start_time
if started is False:
started = True
start_time = time()
print("starting timer")
try:
character = '{0}'.format(key.char)
except AttributeError:
character = '{0}'.format(key)
my_log.append(character)
def listen():
global started
print('keyboard listener is initialized')
with keyboard.Listener(on_press=on_press):
while True:
if started:
now = time()
if now - start_time > 10:
break
return # end our listener
listen()
print("done listening")
print(my_log)
示例输出看起来像(有点乱,因为打印与键入的内容相结合):
keyboard listener is initialized
astarting timer
bcdefghijklmnopqrstuvwxyzdone listening
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']