有没有不删除完整堆栈的 lua-c api 函数？

Question

我的问题是 lua_pcall 清除了堆栈，因为我想在再次调用之前重用堆栈，只需再次更改一次。
有没有一种方法可以复制完整的堆栈并再次粘贴，甚至可以在不清除堆栈的情况下调用 lua 函数？

Lua:

function test(a)
    print(a)
end

event.add("test", test)
event.add("test", test)

event.call("test", 42)

C++:

int Func_Event_call(Lua_State* L){

    //Stack: String:Eventname, Arguments...

    std::string name = luaL_checkstring(L, 1);

    ... Get array functions from name

    for(...){

        //load function into stack
        lua_rawgeti(L, LUA_REGISTRYINDEX, functions[c]);
        lua_replace(L, 1);

        //Wanted Stack: Lua_Function, Arguments... <- works for the first function

        //call function
        lua_pcall(L, nummberArgs, 0, 0);

        //stack is now empty because of lua_pcall <- problem
    }

    return 0;
}

Answer 1

    //store stack in Registry
    lua_createtable(L, nummberArgs, nummberArgs);
    lua_insert(L, 1);

    //fill table
    for (int c = 0; c < nummberArgs; c++) {

        lua_pushinteger(L, c);
        lua_insert(L, -2);
        lua_settable(L, 1);

    }

    //store it in Registry and clean up
    int reg_key = luaL_ref(L, LUA_REGISTRYINDEX);
    lua_remove(L, 1);

    ...

    //restore stack from above
    lua_rawgeti(L, LUA_REGISTRYINDEX, reg_key);

    //iterate over the table to get all elements, the key is getting removed by lua_next
    lua_pushnil(L);
    while (lua_next(L, 1) != 0) {
        /* uses 'key' (at index -2) and 'value' (at index -1) */
        /* move 'value'; keeps 'key' for next iteration */
        lua_insert(L, -2);
    }

    //remove table from stack
    lua_remove(L, 1);

我通过在注册表中使用 table 解决了这个问题，并将完整的堆栈放入带有数字键的 table 中。调用第二部分后，我可以返回调用第一部分时的堆栈，但是多次。

有没有不删除完整堆栈的 lua-c api 函数？

Is there a lua-c api function which doesn't remove the complete stack?

lua

luac