在 Scrapy 中发送 Post 请求

Question

我正在尝试从 google Play 商店中抓取最新评论，为了获得这些评论，我需要发出 post 请求。

使用 Postman，效果很好，我得到了想要的回复。

但是终端中的 post 请求给我一个服务器错误

例如：此页面 https://play.google.com/store/apps/details?id=com.supercell.boombeach

curl -H "Content-Type: application/json" -X POST -d '{"id": "com.supercell.boombeach", "reviewType": '0', "reviewSortOrder": '0', "pageNum":'0'}' https://play.google.com/store/getreviews

出现服务器错误并且

Scrapy 忽略这一行：

frmdata = {"id": "com.supercell.boombeach", "reviewType": 0, "reviewSortOrder": 0, "pageNum":0}
        url = "https://play.google.com/store/getreviews"
        yield Request(url, callback=self.parse, method="POST", body=urllib.urlencode(frmdata))

Answer 1

确保 formdata 中的每个元素都是 string/unicode

类型

frmdata = {"id": "com.supercell.boombeach", "reviewType": '0', "reviewSortOrder": '0', "pageNum":'0'}
url = "https://play.google.com/store/getreviews"
yield FormRequest(url, callback=self.parse, formdata=frmdata)

我想这样就可以了

In [1]: from scrapy.http import FormRequest

In [2]: frmdata = {"id": "com.supercell.boombeach", "reviewType": '0', "reviewSortOrder": '0', "pageNum":'0'}

In [3]: url = "https://play.google.com/store/getreviews"

In [4]: r = FormRequest(url, formdata=frmdata)

In [5]: fetch(r)
 2015-05-20 14:40:09+0530 [default] DEBUG: Crawled (200) <POST      https://play.google.com/store/getreviews> (referer: None)
[s] Available Scrapy objects:
[s]   crawler    <scrapy.crawler.Crawler object at 0x7f3ea4258890>
[s]   item       {}
[s]   r          <POST https://play.google.com/store/getreviews>
[s]   request    <POST https://play.google.com/store/getreviews>
[s]   response   <200 https://play.google.com/store/getreviews>
[s]   settings   <scrapy.settings.Settings object at 0x7f3eaa205450>
[s]   spider     <Spider 'default' at 0x7f3ea3449cd0>
[s] Useful shortcuts:
[s]   shelp()           Shell help (print this help)
[s]   fetch(req_or_url) Fetch request (or URL) and update local objects
[s]   view(response)    View response in a browser

Answer 2

在 Scrapy 中使用 Post 的示例页面遍历：

def directory_page(self,response):
    if response:
        profiles = response.xpath("//div[@class='heading-h']/h3/a/@href").extract()
        for profile in profiles:
            yield Request(urljoin(response.url,profile),callback=self.profile_collector)

        page = response.meta['page'] + 1
        if page :
            yield FormRequest('https://rotmanconnect.com/AlumniDirectory/getmorerecentjoineduser',
                                        formdata={'isSortByName':'false','pageNumber':str(page)},
                                        callback= self.directory_page,
                                        meta={'page':page})
    else:
         print "No more page available"

Answer 3

上面的回答并没有真正解决问题。他们将数据作为参数发送，而不是 JSON 数据作为请求的主体。

来自http://bajiecc.cc/questions/1135255/scrapy-formrequest-sending-json：

my_data = {'field1': 'value1', 'field2': 'value2'}
request = scrapy.Request( url, method='POST', 
                          body=json.dumps(my_data), 
                          headers={'Content-Type':'application/json'} )

在 Scrapy 中发送 Post 请求

Send Post Request in Scrapy

python

web-crawler

scrapy

python-3.x