批量替换字符串但同时删除空行

Question

我有一个改编自@MC ND 的批处理，用于搜索字符串并在给定文件中替换它。

除了删除我初始文件中的空行外，它运行良好。

@echo off 
setlocal enableextensions disabledelayedexpansion

set "search=To_be_replaced"
set "replace=Well_Replaced"
set "File=TEST.txt"

for /f "delims=" %%i in ('type "%File%" ^& break ^> "%File%" ') do (
    set "line=%%i"

    setlocal enabledelayedexpansion
    >>"%File%" echo(!line:%search%=%replace%!
    endlocal
)

输入文件是：

A

To_be_replaced

B

我希望输出为：

A

Well_Replaced

B

实际输出为：

A
Well_Replaced
B

如何才能不删除空行？

Answer 1

这是一个基于目前评论的示例：

@Echo Off
SetLocal EnableExtensions DisableDelayedExpansion

Set "search=To_be_replaced"
Set "replace=Well_Replaced"
Set "File=TEST.txt"

For /F "Tokens=1*Delims=]" %%A In ('Find /V /N ""^<"%File%"^&Break^>"%File%"'
)Do (Set "line=%%B"
    SetLocal EnableDelayedExpansion
    (If Not "%%B"=="" (Echo(!line:%search%=%replace%!)Else Echo()>>"%File%"
    EndLocal)

批量替换字符串但同时删除空行

Batch replaces string BUT also deletes blank lines

batch-file

replace

blank-line