Objective C launchApplicationAtUrl 参数不起作用
Objective C launchApplicationAtUrl arguments not working
我想通过 launchApplicationAtURL 使用一些参数打开 Photoshop 应用程序。 Photoshop 已打开,但我在参数列表中指定的图像未打开。
NSWorkspace *workspace = [NSWorkspace sharedWorkspace];
NSString *urlString = [NSString stringWithUTF8String:imageEditorPath.GetPlatformString().c_str()];
NSURL *url = [[NSURL alloc] initFileURLWithPath:urlString];
//Handle url==nil
NSError *error = nil;
NSArray *arguments = [NSArray arrayWithObjects:@"/Users/admin/q/177381.png", nil];
[workspace launchApplicationAtURL:url options:0 configuration: [NSDictionary dictionaryWithObject:arguments forKey:NSWorkspaceLaunchConfigurationArguments] error:&error];
中日韩回答正确:
[[NSWorkspace sharedWorkspace] openURLs:fileURLs withApplicationAtURL:appURL options:0 configuration:0 错误:&err];其中 fileURLs 是要打开的文件数组,appURL 指向应用程序。 – 中日韩
CJK - 请作为答复发送。
参考我上面的评论,可以使用 NSWorkspace
方法 openURLs:withApplicationAtURL:options:configuration:error:
. If you don't need to send any arguments to the application, or set environment variables for the app, then one can simply pass NULL
to the configuration:
parameter. Likewise, there are a multitude of NSWorkspaceLaunchOptions
available 在一个应用程序中打开多个文件,但如果需要 none 个,可以通过 0
到 options:
参数:
NSURL *appURL = [NSURL fileURLWithPath:@"file:///path/to/application.app"];
NSArray *fileURLs = [NSArray arrayWithObjects:[NSURL fileURLWithPath:@"file:///path/to/file1"],
[NSURL fileURLWithPath:@"file:///path/to/file2"],
nil];
NSError *err = nil;
BOOL success = [[NSWorkspace sharedWorkspace] openURLs:fileURLs withApplicationAtURL:appURL
options:0 configuration:NULL error:&err];
我想通过 launchApplicationAtURL 使用一些参数打开 Photoshop 应用程序。 Photoshop 已打开,但我在参数列表中指定的图像未打开。
NSWorkspace *workspace = [NSWorkspace sharedWorkspace];
NSString *urlString = [NSString stringWithUTF8String:imageEditorPath.GetPlatformString().c_str()];
NSURL *url = [[NSURL alloc] initFileURLWithPath:urlString];
//Handle url==nil
NSError *error = nil;
NSArray *arguments = [NSArray arrayWithObjects:@"/Users/admin/q/177381.png", nil];
[workspace launchApplicationAtURL:url options:0 configuration: [NSDictionary dictionaryWithObject:arguments forKey:NSWorkspaceLaunchConfigurationArguments] error:&error];
中日韩回答正确: [[NSWorkspace sharedWorkspace] openURLs:fileURLs withApplicationAtURL:appURL options:0 configuration:0 错误:&err];其中 fileURLs 是要打开的文件数组,appURL 指向应用程序。 – 中日韩
CJK - 请作为答复发送。
参考我上面的评论,可以使用 NSWorkspace
方法 openURLs:withApplicationAtURL:options:configuration:error:
. If you don't need to send any arguments to the application, or set environment variables for the app, then one can simply pass NULL
to the configuration:
parameter. Likewise, there are a multitude of NSWorkspaceLaunchOptions
available 在一个应用程序中打开多个文件,但如果需要 none 个,可以通过 0
到 options:
参数:
NSURL *appURL = [NSURL fileURLWithPath:@"file:///path/to/application.app"];
NSArray *fileURLs = [NSArray arrayWithObjects:[NSURL fileURLWithPath:@"file:///path/to/file1"],
[NSURL fileURLWithPath:@"file:///path/to/file2"],
nil];
NSError *err = nil;
BOOL success = [[NSWorkspace sharedWorkspace] openURLs:fileURLs withApplicationAtURL:appURL
options:0 configuration:NULL error:&err];