为什么此代码不起作用以及如何修复它？

Question

我写了一个代码，这是一个简单的程序，有 2 个输入和打印。我添加了一些代码来防止名称和年份是正确的。当来自输入的数据正确时，我的程序可以正常工作，但当它不存在时，有相同的消息并且输入可以再次输入，但是在分配给变量新词之后，打印旧词：/我使用 Python 3.7.3

import re
def name_check(x):
    pattern1=r'[A-Za-z]'
    if re.match(pattern1,x):
        pass
    else:
        print ('This is not your name.')
        give_name()
def year_check(y):
    pattern2=r'(\d)'
    if re.match(pattern2,y):
        pass
    else:
        print ('This is not your year of birth.')
        give_year()
def printing(x,y):
    try:
        print('Hey,',x,',in',int(y)+100,'year you will have 100 years.')
    except:
        print ('An error occured.')
def give_name():
    x=str(input('Enter your name: '))
    name_check(x)
    return x
def give_year():
    y=input('Enter your year of birth: ')
    year_check(y)
    return y
def program():
    x=give_name()
    y=give_year()
    printing(x,y)
program()

Answer 1

问题是您只在第一次捕获变量（x 和 y）。试试这个：

import re

def name_check(x):
    pattern1=r'[A-Za-z]'
    if re.match(pattern1,x):
        return True
    else:
        print ('This is not your name.')
        return False

def year_check(y):
    pattern2=r'(\d)'
    if re.match(pattern2,y):
        return True
    else:
        print ('This is not your year of birth.')
        return False

def printing(x,y):
    print(x,y)
    try:
        print('Hey,',x,',in',int(y)+100,'year you will have 100 years.')
    except:
        print ('An error occured.')

def give_name():
    x=str(input('Enter your name: '))
    while not name_check(x):
        x=str(input('Enter your name: '))
    return x

def give_year():
    y=input('Enter your year of birth: ')
    while not year_check(y):
        y=input('Enter your year of birth: ')
    return y

def program():
    x=give_name()
    y=give_year()
    printing(x,y)

program()

Answer 2

在您的程序中，x 和 y 在链函数调用后不会改变。你应该在你的 year_check 和 name_check 函数中使用 return 这样才能对 x 和 y:

生效

def name_check(x):
    pattern1=r'[A-Za-z]'
    if re.match(pattern1,x):
        return x
    else:
        print ('This is not your name.')
        return give_name()
def year_check(y):
    pattern2=r'(\d)'
    if re.match(pattern2,y):
        return y
    else:
        print ('This is not your year of birth.')
        return give_year()
def printing(x,y):
    try:
        print('Hey,',x,',in',int(y)+100,'year you will have 100 years.')
    except:
        print ('An error occured.')
def give_name():
    x=str(input('Enter your name: '))
    return name_check(x)
def give_year():
    y=input('Enter your year of birth: ')
    return year_check(y)
def program():
    x=give_name()
    y=give_year()
    printing(x,y)
program()

为什么此代码不起作用以及如何修复它？

Why this code doesn't work and how to repair it?

python

variables

error-checking

attribution