嵌套函数 - 参数缺少参数

Question

我一直在尝试在另一个函数中创建一个函数，其中 getPoolInfo 的输出将是 (Func1:Double, Func2:Double)。

我真的需要你们的帮助。

func getPoolInfo(PoolLength:Double, PoolWidth:Double, ShallowDepth:Double,DeepDepth:Double)->(Double,Double)
{

//To calculate the Area of the Pool
func Area(PoolLength:Double,PoolWidth:Double)-> Double
{
    let area = PoolLength * PoolWidth
    return area
}

//To calculate the Volume of the Pool
func poolVolume(PoolLength:Double, PoolWidth:Double, ShallowDepth:Double,DeepDepth:Double)->Double{

    let area = PoolLength * PoolWidth
    let avgDepth = ((ShallowDepth + DeepDepth) / 2)
    let volume = area * avgDepth


    return volume
}

return (Area(),poolVolume())

}

getPoolInfo(PoolLength: 12, PoolWidth: 6, ShallowDepth: 1, DeepDepth: 3)

Missing argument for parameter

Answer 1

改变

return (Area(),poolVolume())

至

return (Area(PoolLength:PoolLength,PoolWidth:PoolWidth),poolVolume(PoolLength:PoolLength, PoolWidth:PoolWidth, ShallowDepth:ShallowDepth,DeepDepth:DeepDepth))

嵌套函数 - 参数缺少参数

Nested Functions - missing Argument for parameter

func

swift